Hi. I have a question about Paper 2 Q5b. I got the same answer that is in the solution but i used a different method.
I used the fact the we know the gradient at Q is 4 so i said the Gradient at P will be -4.
If the gradient is negative -4 then x - 8 = -4 therefore x = 4 and the y-coord is the same as Q so the point P is (4,10)
Please let me know if this makes any sense and if i would get the mark for it.
Thanks alot.
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