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2005 Paper 2 Q10
Started by Adam, May 04 2006 07:22 PM
1 reply to this topic
#1
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Site Swot
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Posted 04 May 2006 - 07:22 PM
Can somebody explain how this is done?
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#2
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Fully Fledged Genius
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Posted 04 May 2006 - 09:19 PM
you need to work out a.a (which is just a[^2]
then a.b=|a||b|cosx, where x=60 (equilateral triangle)
and finally a.c= |a||c|cosx, where x=90 (perpendicular)
then a.b=|a||b|cosx, where x=60 (equilateral triangle)
and finally a.c= |a||c|cosx, where x=90 (perpendicular)
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