I can't get the answers to these:
The function x^3-3x+2
find the co-ordinates of a,b,c
find the coordinates of the stationary point d and confirm its nature.
The functions f and g are given as:
f(x) = 4/x-2 and g(x) x+2
what is g(f(x))
Two functions, f and g are definded as follows:
f(x) = x-1 g(x) 1/x^2-1
find g(f(x)


Help
Started by gary, May 19 2005 06:09 PM
6 replies to this topic
#1
Posted 19 May 2005 - 06:09 PM
#2
Posted 19 May 2005 - 06:33 PM
I have no clue if these are absolutely right or not, but i've given it a shot. If their wrong then could someone please correct me
f(x) = 4/(x-2) g(x) = (x+2)
f(g(x))
f(x+2) = 4/(x+2)-2
= 4/x
f(x) = (x-1) g(x) = 1/(x
-1)
f(g(x))
f(1/(x
-1) = 1/x[^2]-1 -1
= 1/x[^2] -2
hope these are ok!

f(x) = 4/(x-2) g(x) = (x+2)
f(g(x))
f(x+2) = 4/(x+2)-2
= 4/x
f(x) = (x-1) g(x) = 1/(x

f(g(x))
f(1/(x

= 1/x[^2] -2
hope these are ok!
#3
Posted 19 May 2005 - 06:34 PM
seem correct to me
If i am not here i am somewhere else
#4
Posted 19 May 2005 - 06:36 PM
for the 1st part on finding the point d differentiate the function and equate to zero
then do a nature table to confirm its nature
then do a nature table to confirm its nature
If i am not here i am somewhere else
#5
Posted 19 May 2005 - 06:43 PM
I thought it was differentiation just had not seen it like that before.
Thanks.
Thanks.
#6
Posted 19 May 2005 - 06:47 PM
It is g(f(x)) sorry.
#7
Posted 19 May 2005 - 06:59 PM
g(f(x))
=g(x-1)
= 1/ (x-1)^2-1
= 1/ x^2-2x+1-1
1/ x^2 - 2x
=g(x-1)
= 1/ (x-1)^2-1
= 1/ x^2-2x+1-1
1/ x^2 - 2x
If i am not here i am somewhere else
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