## 1 + 1 = 1 ? ? ? relaxing ...

### cK_hoangan

Posted 28 November 2007 - 10:29 PM

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

### Jammie1000000

Posted 29 November 2007 - 01:31 PM

QUOTE(cK_hoangan @ Nov 28 2007, 10:29 PM)
This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

### cK_hoangan

Posted 29 November 2007 - 01:45 PM

Well-done !!!!

as I said, it's all for relaxing : D

You wanna try once more with 1 > 4 ? I will prove it soon

### Marcus

Posted 06 January 2008 - 04:01 PM

just to go along the same lines of posting bizarre mathematics, here is a proof that or in fact any number you want

eqn 1) x+1 = 0
eqn 2) 2x+2 = 0

divide eqn 2 by eqn 1

cancel the x+1 on top and bottom to get:

but this = anything helps prove the above problem...

=> (A-B)(A+B)= B (A-B) , (A-B) = 0
=> 0(A+B)= 0B
=>2B = B
so if =2
then this works XD XD

Posted 07 January 2008 - 07:44 PM

Here's a tough one (you'll need to have done complex numbers, can't remember when it comes up in advanced higher):

Where's the error?

### Marcus

Posted 10 January 2008 - 11:43 PM

Right I don't think this is correct but:

and also is usually written as as angles usually lie between and

so when you multiplied the by you were effectively multiplying by which you can't do.

Am i even remotely on the right lines here?

### englisher

Posted 21 February 2008 - 02:55 PM

QUOTE(ad absurdum @ Jan 7 2008, 08:44 PM)
Here's a tough one (you'll need to have done complex numbers, can't remember when it comes up in advanced higher):

Where's the error?

Can't put brackets round e^2ipi ?

### Marcus

Posted 22 February 2008 - 09:16 PM

QUOTE(englisher @ Feb 21 2008, 02:55 PM)
Can't put brackets round e^2ipi ?

I wish it was as simple as that, but yeah you can... one of the rules of indices

in the case of

a would be
and b would be

### Wildespleen

Posted 21 January 2009 - 08:13 PM

Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).
I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

### Marcus

Posted 27 January 2009 - 02:12 PM

QUOTE (Wildespleen @ Jan 21 2009, 08:13 PM) <{POST_SNAPBACK}>
Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).
I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

Yeah , and it comes from Euler's formula: (only briefly mentioned in AH)

I had to ask my uni profs to explain what is wrong with this proof...

### Monkey Man

Posted 02 January 2010 - 06:50 PM

QUOTE Jammie1000000
QUOTE(cK_hoangan @ Nov 28 2007, 10:29 PM) View Post
This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 blink.gif BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... tongue.gif

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

cool.gif

can i just add that this is not dividing through by (A-B), they cancel each other out

### Marcus

Posted 27 January 2010 - 05:37 PM

but they cancel out, because you are dividing through by (a-b) << that the operation you are actually doing when you cancel out terms