"show by solving the following log equation that the exact value of x can be written in the form 4p root p and write down the value of p.

log to the base x (2x) + 2log to the base x of 8 =3"

I started by doing:

log to the base x (2x *64) = 3

log to the base x (128x) = 3

and after that im not really sure... any help appreciated

## log problem

### Nathan

Posted 09 March 2007 - 06:24 AM

Bit of a starter for you;

log

so, by the log

log

is equivalent to log

log

_{x}2x + log_{x}8 = 3so, by the log

_{x}a + log_{x}b = log_{x}ab, ( http://www.hsn.uk.net/files/HSN23300.pdf , page 4 [136] )log

_{x}2x + log_{x}8 = 3is equivalent to log

_{x}16x = 3