[stuck]

"show by solving the following log equation that the exact value of x can be written in the form 4p root p and write down the value of p.

log to the base x (2x) + 2log to the base x of 8 =3"

I started by doing:
log to the base x (2x *64) = 3
log to the base x (128x) = 3


and after that im not really sure... any help appreciated

[Nathan]

Bit of a starter for you;

log_x2x + log_x8 = 3

so, by the log_xa + log_xb = log_xab, ( http://www.hsn.uk.net/files/HSN23300.pdf , page 4 [136] )

log_x2x + log_x8 = 3
is equivalent to log_x16x = 3