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2003 - Written Paper - Q10(c)

sarmad

Posted 20 May 2006 - 08:53 PM

hi, could someone please explain to me how to to do this mole calculation.

Michael

Posted 20 May 2006 - 09:03 PM

It tells you the ratio is 1:3 so there must be 0.3g of I2 in the CHCL3 so:

10cm3 ------> 0.3g
100cm3-----> 3g
1000cm(1l) ----> 30 so the answer is 30gl^-1

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