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2004 Paper 1 Q10 - HSN forum

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2004 Paper 1 Q10


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#1 Misbah

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Posted 18 May 2006 - 05:17 PM

2004 q10 paper 1 help please thanks

#2 Nathan

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Posted 18 May 2006 - 06:01 PM

CE = sqrt.gif 10 hence sinx = 1/ sqrt.gif 10 cosx = 3/ sqrt.gif 10

DEA = 2x +90

cosDEA = cos(2x+90)

cos(2x+90) = cos2xcos90 - sin2xsin90
= -sin2x = -2sinxcosx
=-2*(1/ sqrt.gif 10) * 6/ sqrt.gif 10
= -6 / 10

#3 Misbah

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Posted 18 May 2006 - 07:25 PM

QUOTE(nathanm @ May 18 2006, 07:01 PM) View Post

CE = sqrt.gif 10 hence cosx = 1/ sqrt.gif 10 sinx = 3/ sqrt.gif 10

DEA = 2x +90

cosDEA = cos(2x+90)

cos(2x+90) = cos2xcos90 - sin2xsin90



hey i got up to there aswell but how do u get the bit aftr tht

#4 Dave

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Posted 18 May 2006 - 07:48 PM

use trig identitites for cos2x and replace cos 90 and sin 90 with there exact values

If i am not here i am somewhere else



#5 Gillz

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Posted 01 January 2007 - 08:01 PM

QUOTE(nathanm @ May 18 2006, 06:01 PM) View Post

CE = sqrt.gif 10 hence sinx = 1/ sqrt.gif 10 cosx = 3/ sqrt.gif 10

DEA = 2x +90

cosDEA = cos(2x+90)

cos(2x+90) = cos2xcos90 - sin2xsin90
= -sin2x = -2sinxcosx
=-2x (1/ sqrt.gif 10) x 6/ sqrt.gif 10
= -6 / 10


The second last line should be changed to -2 * (1/ sqrt.gif 10) * (3/ sqrt.gif 10)





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