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2005 P2 Q7


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#1 UncleJohnny

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Posted 18 May 2006 - 03:09 PM

log4(5-x)-log4(3-x)=2 X<2

ugh I keep getting the wrong answer. Can anybody help?

Oh and i forgot how to do this one:
cos2x=7/25 (non-calc)

#2 Nathan

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Posted 18 May 2006 - 03:39 PM

(5-x)/(3-x) = 16

5-x = 48 - 16x

15x = 43

x = 43/15

also;

cos2x= 7/25
2cos2x - 1 = 7/25
2cos2x = 32/25
cos2x = 16/25
cosx = 4/5

#3 SncZ

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Posted 18 May 2006 - 03:41 PM

QUOTE(nathanm @ May 18 2006, 04:39 PM) View Post

(5-x)/(3-x) = 16

5-x = 48 - 16x

15x = 43

x = 43/15



umm no its 17x = 43

as: log4(5-x)-log4(3-x)=2 X<2
using 2nd rule of logs, log4 (5-x)/(3-x) =2
therefore.gif 42 = (5-x)/(3-x)

cross multiply to get 48-16x=5-x
43-17x=0
17x=43
x=43/17=2
wink.gif

#4 Nathan

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Posted 18 May 2006 - 03:45 PM

no, i meant 43/15

#5 UncleJohnny

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Posted 18 May 2006 - 03:50 PM

Thanks alot guys, i just really lose m mind sometimes but coldplay seems to help......





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