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2003 paper 2 Q7 - HSN forum

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2003 paper 2 Q7


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#1 Jilly90

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Posted 17 May 2006 - 06:58 PM

in the 2003 paper 2 question 7, i know how to do these qestions but cant seem to get what a is the answer is 68.2 but i seem to get 21.8 because ksina/kcosa is 2/5 giving me tana=2/5 which is 21.8. where am i goin wrong? if this makes any sense, please help!

#2 Nathan

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Posted 17 May 2006 - 07:04 PM

it should be ksina=5,kcosa=2

so then it's 5/2

and that gives you 68.2

#3 Jilly90

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Posted 17 May 2006 - 07:07 PM

thats would make sense but why is that? because the equation is 2sinx + 5cosx shouldnt ksinx =2 and kcosx =5?

#4 Nathan

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Posted 17 May 2006 - 07:09 PM

QUOTE(Jilly90 @ May 17 2006, 08:07 PM) View Post

thats would make sense but why is that? because the equation is 2sinx + 5cosx shouldnt ksinx =2 and kcosx =5?


when you expand ksin(x+a), you get k sinx cosa + k cosx sina

#5 Jilly90

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Posted 17 May 2006 - 07:16 PM

am still unsure unsure.gif

just looked at ma notes know where am goin wrong now! thanx





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