**Calculate the speed at which the reletavistic mass of an object is equal to three times its rest mass.**

There is no other information in the question. It is worth 2 marks. Can anyone help me here?

Thank you!

Posted 12 May 2006 - 07:58 AM

I am probably missing something obvious here but I do not get this question.

**Calculate the speed at which the reletavistic mass of an object is equal to three times its rest mass.**

There is no other information in the question. It is worth 2 marks. Can anyone help me here?

Thank you!

There is no other information in the question. It is worth 2 marks. Can anyone help me here?

Thank you!

Posted 12 May 2006 - 10:57 AM

since the relativistic mass is equal to 3 times the rest mass, you can replace m in the equation for 3mo

i.e

3 mo = ( mo / (1- (v^2 / c^2))^1/2

then rearrange to get:

3 mo * (1 - (v^2/c^2))^1/2 = mo

so divide through by 3 mo to get

(1 - (v^2 / c^2))^1/2 = 0.333 (a third)

so (1 - (v^2 / c^2)) = 0.111 (square both sides)

so (v^2 / c^2) = 0.888

so (V^2) = 0.888 * c^2

= 8*10^16

therefore v = 2.83*10^8 ms-1

sorry I don't know how to show square root signs and things so it is a bit confusing but I hope this helps!

i.e

3 mo = ( mo / (1- (v^2 / c^2))^1/2

then rearrange to get:

3 mo * (1 - (v^2/c^2))^1/2 = mo

so divide through by 3 mo to get

(1 - (v^2 / c^2))^1/2 = 0.333 (a third)

so (1 - (v^2 / c^2)) = 0.111 (square both sides)

so (v^2 / c^2) = 0.888

so (V^2) = 0.888 * c^2

= 8*10^16

therefore v = 2.83*10^8 ms-1

sorry I don't know how to show square root signs and things so it is a bit confusing but I hope this helps!

Posted 12 May 2006 - 10:08 PM

for the coding follow this link:

latex coding

click on the images of the coding and you will be shown how they write it

latex coding

click on the images of the coding and you will be shown how they write it