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Can someone pelase help with this problem?
Electrons are accelerated through a large potential difference of 7.5x10^5V. The electronas are initially at rest. Calculate the speed reached by these electrons.
Wouldn't you need more information?
I thought about writing just under the speed of light but there is another quesiron like this.
Thanks
Ian
Quick Quesiton
, the accelerating force IS the electric field due to the potential difference, me thinks.
werlop
Posted 13 November 2005 - 10:06 PM
Well from what I did the electron would end up faster than c and obviously that isn't going to happen, as as v tends to c, m tends to infinity, etc.
That's why I'm suggesting that either you need to consider relativistic effects or I have done something stupid.
That's why I'm suggesting that either you need to consider relativistic effects or I have done something stupid.
Jason Bourne
Posted 19 January 2006 - 03:25 PM
![\[
\begin{array}{l}
QV = \frac{1}{2}mv^2 \\
v = \sqrt {\frac{{2QV}}{m}} \\
v = \sqrt {\frac{{2 \times \left( {1.6 \times 10^{ - 19} } \right) \times \left( {7.5 \times 10^5 } \right)}}{{9.11 \times 10^{ - 31} }}} \\
\end{array}
\]](/latexrender/pictures/3f3a17fd91a1794bf94c6577e106c7f4.gif "\[
\begin{array}{l}
QV = \frac{1}{2}mv^2 \\
v = \sqrt {\frac{{2QV}}{m}} \\
v = \sqrt {\frac{{2 \times \left( {1.6 \times 10^{ - 19} } \right) \times \left( {7.5 \times 10^5 } \right)}}{{9.11 \times 10^{ - 31} }}} \\
\end{array}
\]")
[right]
[/right][/quote]
Where did you get these math graphics from that i cant find anywhere how to properly make.
George
Posted 19 January 2006 - 05:03 PM
QUOTE(Jason Bourne @ Jan 19 2006, 03:25 PM)
Where did you get these math graphics from that i cant find anywhere how to properly make.
I posted a quick introduction here: http://www.hsn.uk.net/forum/index.php?show...indpost&p=65413
