I would greatly appreciate it if someone could answer this question

Write an expression for the radial acceleration of a particle moving in a circle of radius r, with a speed of v

Hence show that the centrapertal force F acting on this particle of mass m is inversly proportional to the square of the period T

Thanks a lot

Ian

## Deriving Equation

### dfx

Posted 11 October 2005 - 09:01 PM

However, I have a question.

We know that F = ( mv ) / r .

Say instead of v we substitute r.

So we know that V = ( 2 r ) / T r = vT/2

So F = ( m v ) / r = ( m v 2 ) / vT = ( m v 2 ) / T

So is this not contradictory to our previous conclusion? In this case F is inversely proportional to T only.

We know that F = ( mv ) / r .

Say instead of v we substitute r.

So we know that V = ( 2 r ) / T r = vT/2

So F = ( m v ) / r = ( m v 2 ) / vT = ( m v 2 ) / T

So is this not contradictory to our previous conclusion? In this case F is inversely proportional to T only.

### werlop

Posted 12 October 2005 - 09:52 AM

QUOTE(dfx @ Oct 11 2005, 10:01 PM)

However, I have a question.

We know that F = ( mv ) / r .

Say instead of v we substitute r.

So we know that V = ( 2 r ) / T r = vT/2

So F = ( m v ) / r = ( m v 2 ) / vT = ( m v 2 ) / T

So is this not contradictory to our previous conclusion? In this case F is inversely proportional to T only.

We know that F = ( mv ) / r .

Say instead of v we substitute r.

So we know that V = ( 2 r ) / T r = vT/2

So F = ( m v ) / r = ( m v 2 ) / vT = ( m v 2 ) / T

So is this not contradictory to our previous conclusion? In this case F is inversely proportional to T only.

I did this really quickly so may have made a mistake, but it still works even if you substitute r: