7 replies to this topic

[SomethingTypical]

I can never do these questions. Could someone please give me a full solution?

[Dave]

A = A_o e^kt

if it says the area doubles then you can say that

a_o = 1
a = 2

as this sticks to rule

then just sub in these values

2 = 1.e^kt

you can also sub in your value for t given in question

2 = e^1.5k

to find k we need to get it down from the exponent. To do with we need to cancel off the
e. This can be doen by taking the logs of both sides

ln 2 = 1.5k
k = ln 2 / 1.5
k = 0.46

[SomethingTypical]

Thanks, I think I may be getting the hang of these. Hopefully there'll not be one tomorrow.

[gary]

There was a question similar to this la year doubt one will be there this year will most likely be a graph which is worse.

[tupacshakur]

There was a question similar to this la year doubt one will be there this year will most likely be a graph which is worse.

just cos something was in it last year doesnt mean it might not come up again.

are u meaning the graphs were u have to find a and b from log equations and the graphs where u have to get it into the special forumula and say what k and n is?

[SomethingTypical]

There was a question similar to this la year doubt one will be there this year will most likely be a graph which is worse.

I thought that myself but you can never be too sure.

[tupacshakur]

you wont think the same type of "collinear" question would of come up in 2003 AND 2004 but it did so these things happen.

[SomethingTypical]

The only reason I assumed that it wouldn't come up because it came up in 2001 and then in 2004. I know how to do it now but I still would rather that it didn't turn up again.