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2003, Paper I, Q7 - HSN forum

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2003, Paper I, Q7


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#1 herbeey

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Posted 19 May 2005 - 01:20 PM

How do I prove that they DON'T intersect?
I know generally what to do, but I don't know how to use it to conclude this.
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#2 SomethingTypical

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Posted 19 May 2005 - 01:57 PM

Make the two equations equal to each other.
Make them = 0
Then use b² - 4ac

If the answer is less than 0, then there's no intersection.

#3 herbeey

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Posted 19 May 2005 - 02:01 PM

Right. That's what I did, but I see now that my problem is; what value of 'x' do I use for the discriminant?
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#4 SomethingTypical

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Posted 19 May 2005 - 02:07 PM

Ok, my solution is

x(sq) + x + 3

So a = 1
b = 1
c = 3

1(sq) - 4*1*3 = 0
= -11

-11<0 So no point of intersection.

#5 herbeey

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Posted 19 May 2005 - 02:10 PM

oh! Sorry! I'm having a bad maths day today,... I totally forgot that it is the factors of x which equal a, b, c.... I was thinking that b=x, not 1!
Cheers.
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#6 SomethingTypical

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Posted 19 May 2005 - 02:10 PM

QUOTE(herbeey @ May 19 2005, 03:10 PM)
oh! Sorry! I'm having a bad maths day today,... I totally forgot that it is the factors of x which equal a, b, c....
Cheers.

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No problem, I think most people are having a bad maths day today. smile.gif


#7 Steve

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Posted 19 May 2005 - 03:11 PM

QUOTE(SomethingTypical @ May 19 2005, 03:10 PM)
No problem, I think most people are having a bad maths day today. smile.gif

I suppose that's better than having one tomorrow sad.gif
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