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2003 Paper 1 Question 6 - HSN forum

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2003 Paper 1 Question 6


4 replies to this topic

#1 tupacshakur

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Posted 16 May 2005 - 03:54 PM

how do u do this question?

I can only get as far as doing AB=b-a which i got an answer to.
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#2 Dave

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Posted 16 May 2005 - 04:02 PM

ok then this is section formula i think not that i can remember it

if you look at the line you have AB and AD

AD is 3 times the size of AB

You know AB (3,2,-1)

so you can work out AD as its 3 times (3,2,-1) which gives (9,6,-3)

to find the point D

AD = d - a
(9,6,-3) = (x,y,z) - ( -1,-3,2)

which gives D(8,3,-1)

hope you can understand this

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#3 tupacshakur

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Posted 16 May 2005 - 04:07 PM

thanks! biggrin.gif
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#4 AppleCore

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Posted 17 May 2005 - 10:43 PM

i just kept adding to AB till i got to D if u get me!

#5 Dave

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Posted 18 May 2005 - 10:05 AM

same thing as i did really except i did it in one go

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