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2001 Paper 1 Q. 10 - HSN forum

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2001 Paper 1 Q. 10


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#1 gary

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Posted 16 May 2005 - 10:03 AM

Help please.

#2 Dave

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Posted 16 May 2005 - 12:24 PM

i have already doen the solution to this one

the thread is found http://www.hsn.uk.net/forum/index.php?showtopic=2052

If i am not here i am somewhere else



#3 gary

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Posted 16 May 2005 - 01:34 PM

Thats for paper 2.

#4 AppleCore

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Posted 17 May 2005 - 09:36 PM

Question 10 Part (a)

y = log 2 (x)
log 2 8 = 3
thus b = 3

and as in all simple log equations the point on the x axis is always (1,0) just as in a simple quadratic equation y = x² the point on the y axis is (0,1).


#5 AppleCore

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Posted 17 May 2005 - 09:43 PM

Question 10 part (b)

y = log 2 (x+1) -3

(x + 1) will mean that the graph moves 1 point to the left making the points (8,3) become (7,3) and (1,0) become (0,0)

then the -3 is the position of the y axis which means the graph moves 3 down. making the (0,0) become (0,-3) and the (7,3) become (7,0)

#6 Dave

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Posted 17 May 2005 - 09:49 PM

lol look at that so it is

i wonder why i thought it was paper 2

If i am not here i am somewhere else







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