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2004 p2 Q11 - HSN forum

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2004 p2 Q11


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#1 eck231

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Posted 08 May 2005 - 02:03 PM

I noticed there was an earlier thread on this question but i don't even no how to begin it!

Could someone possibly put up a solution for the full question please!

Thanks very much!

#2 Mr H

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Posted 08 May 2005 - 03:26 PM

I was going to start typing but here's a link to someone who has done that already!

http://www.mathsrevision.com/index_files/M...2004_paper2.pdf

H tends 2 infinity

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#3 coca

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Posted 08 May 2005 - 03:37 PM

I already started to type smile.gif

To get the limits, find where y=2x-1/2x^2 and y=1.5 collide.

2x-1/2x^2 = 1.5
4x-x^2 = 3
-x^2 + 4x - 3 = 0
(-x+3)(x-1)=0
Limits: x=3, x=1

then integrate y=2x-1/2x^2

and get this:

[x^2 - x^3/6] upper limit: 3, lower: 1
area = (9 - 27/6) - (1-1/6)
area = 3+2/3

then you need to subtract the area of the box underneath the segment:

area of box = 2*1.5 = 3

so area of segment = 3+2/3 - 3 = 2/3 metres^2.
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