2004 - papaer 1 - question 7
Posted 02 May 2005 - 02:58 PM
find integral value between 2 and 0 for square root of (4x+1) dx.
Ive gone thro all the workin but i cant get the answer to come out rite
i keep getting 52/3 unit 2 wen it should be 26/6 unit 2.
Any help given is greatly appreciated.
Posted 02 May 2005 - 02:59 PM
Must be doing something wrong but don't know what !
Help is much appreciated with me too !
Posted 02 May 2005 - 03:11 PM
the bit you are forgetting is that when you interate ax+b you get 1/a (ax+b)
so they get here
2/3 * 1/4 * (4x+1) 3
when you sub in the parameters you get your 26/6
If i am not here i am somewhere else
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