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2004 - papaer 1 - question 7 - HSN forum

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2004 - papaer 1 - question 7


3 replies to this topic

#1 eck231

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Posted 02 May 2005 - 02:58 PM

HEy the questions is

find integral value between 2 and 0 for square root of (4x+1) dx.

Ive gone thro all the workin but i cant get the answer to come out rite

i keep getting 52/3 unit 2 wen it should be 26/6 unit 2.

Any help given is greatly appreciated.

#2 JiLL

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Posted 02 May 2005 - 02:59 PM

Heya. i keep getting that answer too!

Must be doing something wrong but don't know what !

Help is much appreciated with me too !

thanx dry.gif
beast

#3 Dave

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Posted 02 May 2005 - 03:11 PM

integral.gif sqrt.gif (4x+1)dx

the bit you are forgetting is that when you interate ax+b you get 1/a (ax+b)

so they get here

2/3 * 1/4 * sqrt.gif (4x+1) 3

when you sub in the parameters you get your 26/6

If i am not here i am somewhere else



#4 eck231

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Posted 02 May 2005 - 04:47 PM

sorry, dont really understand that?





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