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#1 kimmy72889

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Posted 05 April 2005 - 10:26 AM

has anyone done this one?

im getting an answer but its the wrong one sad.gif

#2 werlop

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Posted 05 April 2005 - 10:32 AM

Is that supposed to be cos (2x) or cos ^2 (x)

I'm assuming you mean the former, yes?
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#3 kimmy72889

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Posted 05 April 2005 - 10:54 AM

yeah 3cos(2x)

#4 Dave

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Posted 05 April 2005 - 11:10 AM

3cos(2x)+cosx = -1

sub in expansion of cos(2x) = 2cos2x-1

3(2cos2x-1) + cos x = -1

6 cos2x + cos x - 3 = -1


6 cos2x + cos x - 2 = 0

factorise

(3cosx + 2)(2cosx - 1) = 0

3cos x + 2 = 0 2cosx - 1=0

x = 131.8 and 228.2 x = 60, 300

If i am not here i am somewhere else



#5 kimmy72889

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Posted 05 April 2005 - 11:13 AM

thank you smile.gif

#6 Dave

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Posted 05 April 2005 - 11:14 AM

so is that right then!

If i am not here i am somewhere else



#7 kimmy72889

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Posted 05 April 2005 - 11:15 AM

yes perfect (as usual tongue.gif )





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