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2003 paper 1 Q's 10b and 11b - HSN forum

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2003 paper 1 Q's 10b and 11b


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#1 Blind

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Posted 15 February 2005 - 02:55 PM

Could someone please explain to me how to do 2003, paper 1, question 10(b) and 11(b)

Its driving me nuts and I cannot get fathom how to do them.

Thanks

#2 Dave

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Posted 15 February 2005 - 03:36 PM

for these questions tryand use the first pasrt as a clue of what to do.

in part you were to find sin(2p) and cos (2p), the thing that should spring to find is that sin(2p)/cos(2p) = tan (2p)

We also know that to find the gradient of the line its = tan 2p

therefore: sin(2p)/cos(2p) = m

sub in values from part a and simplify

for 11b

q is -24 which i worked out from multipling the two roots together however i dont really know what to do on this one

for p i then took what i had px2 - 24px = y and sub in my point A

this will give

144p-288p=-5
-144p=-5
p = 5/144

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#3 Dave

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Posted 15 February 2005 - 04:02 PM

moderator notice: In the maths forum we have a past paper sub-forum (ie here) where people have already posted a number of questions they have had problems with it may be an idea to search through here before posting as someone will propably have had problems with that question before

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#4 Blind

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Posted 15 February 2005 - 10:09 PM

Thanks, that really helped. Sorry if I posted in the wrong forum: I was pretty stressed when I posted. I'll pay more attention next time.

#5 Dave

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Posted 15 February 2005 - 10:11 PM

Nah its not a problem, this sub-forum hasn't been used for ages and you are new so cool smile.gif

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#6 Ally

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Posted 15 February 2005 - 10:21 PM

Ah yes, I remember that 11(b) question. It pissed me off quite a bit last year.

#7 Dave

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Posted 15 February 2005 - 10:25 PM

yeah i know i really had to say sorry i dont know the answer...how embarressing would that have been rolleyes.gif

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