Jump to content


cK_hoangan's Content

There have been 16 items by cK_hoangan (Search limited from 29-November 20)


By content type

See this member's

Sort by                Order  

#100668 Who belives SOMETHING = NOTHING ?

Posted by cK_hoangan on 17 January 2008 - 03:47 PM in Mathematics

but ... then, wat is the error ? unsure.gif

If you agree that it is an infinite serie, how could you know the number of its terms is changed ? smile.gif




#100621 Quark and Bohr model

Posted by cK_hoangan on 19 December 2007 - 11:10 PM in Physics

I got stuck at 2 things.

Pls, is there anyone explain briefly for me:

What is quark ?

What the meaning of Bohr model ?




#100600 2001 Q21

Posted by cK_hoangan on 04 December 2007 - 07:05 PM in Physics

Definitely, you're right.

Acceleration always goes the same direction with its own force. Therefore, the horizontal acceleration has to work out from the horizontal force. There is no point to pick up the horizontal acceleration with the 4N force, they are all different direction

Generally, You are right, well-done! biggrin.gif : .



#100596 Pls HELP on differentiation

Posted by cK_hoangan on 30 November 2007 - 08:26 PM in Mathematics

1. y = cos (3x - pi/6)- cos2 ( tan (x) ) - sin (pi/3) , dy/dx = ?

2. y= (ln2 (x) + lnx + 1)^1/2 , dy/dx = ?

3. y= ( tan (3x) - cotg (3x) )^1/2, dy/dx = ?



#100592 Who belives SOMETHING = NOTHING ?

Posted by cK_hoangan on 29 November 2007 - 02:04 PM in Mathematics

SOMETHING = NOTHING, it's possible !!! Let see the magic of Maths now :

Consider :

S = 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 +.....
=> 1/2 S = 1/4 + 1/6 + 1/8 + .....
=>S - 1/2S = 1/2 + 1/3 + 1/5 + 1/7 + .... (canceled respectly 1/4; 1/6; 1/8; ... from S by 1/2 S)
=> 1/2 S = 1/2 + 1/3 + 1/5 + 1/7 + ...
Now we subtract the second 1/2 S for the first 1/2 S :

1/2 S - 1/2 S = (1/2 + 1/3 + 1/5 + 1/7 + ... ) - ( 1/4 + 1/6 + 1/8 + ... )
1/2 S - 1/2 S = 1/2 + 1/3 + 1/5 + 1/7 + ... - 1/4 - 1/6 - 1/8 - ...
0 = 1/2 + ( 1/3 - 1/4) + ( 1/5 - 1/6) + ( 1/7 - 1/8 ) + ....
0 = 1/2 + 1/12 + 1/30 + 1/56 + ....

From now. obviously seeing that the right hand side would end up with a positive number which (of course) is greater than 0 unsure.gif . But on the left hand side, so funny, it's definetly 0. blink.gif ( what else can be if subtract 1/2 S by itself ? dry.gif )


So, can u now get the point ? Clearly, NOTHING = SOMETHING , MATHS is miracle !!!! ohmy.gif



#100591 1 + 1 = 1 ? ? ?

Posted by cK_hoangan on 29 November 2007 - 01:45 PM in Mathematics

Well-done !!!! rolleyes.gif

as I said, it's all for relaxing : rolleyes.gifD

You wanna try once more with 1 > 4 ? I will prove it soon tongue.gif



#100588 1 + 1 = 1 ? ? ?

Posted by cK_hoangan on 28 November 2007 - 10:29 PM in Mathematics

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 blink.gif BINGO !!!




I think we shouldn't study Maths anymore cause It's all wrong now ... tongue.gif



#100587 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 09:39 PM in Mathematics

To ad absurdum :

Thank you. I'm really grateful.

I'm in exciting mood and a wee bit apprehensive state. Somehow, I'm quite confident of my Maths knowledge, it's due to our 'crazy' curriculum about Maths in my country e.g. We have to remember over 100 rules and theorems of Maths such as A^3 + B^3 = ... ; cos2x=cos2 (x) - sin2 (x)=2cox2 (x)-1 ; ...etc and etc ...

All my trouble now is about language. I haven't got enough "maths terms" to use in the BMO, therefore I'm worry about my explanation when solving problems.

I did look up of some past paper of BMO. It's required a lot of knowledge in Arithmetic which is so ironically my weakness ...

Anyway, let see wat happen ...

Thank you once again.









#100581 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 07:25 PM in Mathematics

Wikipedia isn't an ideal one. There's only the definition of it. What I need further about its properties, how it works and applies to solve problems.

BMO stands for British Mathematics Olympiad. I suppose you heard about it.

I have plenty of question in Maths but they're quite beyond the AH level. I wonder is it OK if I post it here...



#100579 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 06:00 PM in Mathematics

To Geogre:

I'm Vietnamese. I've just been in UK for a couple of months: exchanged student ...

My English's terrible. First few days coming here, I couldn't hear anythings, neither speaking ...

But I'm learning ... so far...

I'm 17. I attempt to go to uni in UK. With 5 subjects I'm taking now, 2 AH and 3 H I'm quite confident.

I'm really keen on Maths, so interested in me. This Friday I'm going to sit in BMO ... Do you know any website or resource I can search for Modulo. I need further about it but couldn't find out any books mention about it.




#100578 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 05:46 PM in Mathematics

For iain :

I got your point. But the question is really y=(lnx)^(x^0,5) which George's done very well.

but u's right, if the question's in the form y = ln (x^(x^0.5)), it's really similar to AH maths.




#100575 how do you integrate...

Posted by cK_hoangan on 28 November 2007 - 01:01 PM in Mathematics

Oh thanks, silly me, forgot the chain rule, so careless !!!



#100574 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 01:00 PM in Mathematics

what u got for the first question? I mean the final result ... I got it but it's so messy, a loads ...



#100573 differential questions ...

Posted by cK_hoangan on 28 November 2007 - 12:55 PM in Mathematics

I'm really impressed. How old r u ?

By the way, actually, when u reach to sin3 (x) + cos3 (x) / ( cos (x) + sin (x)) we do have a shorter way to simplify :

Remember : sin3 (x) + cos3 (x) = (sin (x) + cos (x)) (sin2 (x) - sinxcosx + cos2 (x)) A^3 + B^3=(A+B)(A^2-AB+B^2)
= (sin (x) + cos (x)) (1 - sinxcosx) sin2 (x) + cos2 (x) = 1
= (sin (x) + cos (x)) (1 - 1/2 sin (2x)) sin (2x) = 2 sinx cosx

hence ((sin (x) + cos (x)) will be simplified to end up with the form y = 1-1/2 sin (2x). YEAH ! You're right !!!


P/s: how could u type power and fraction when posting ? I'm a newcomer ...






#100569 differential questions ...

Posted by cK_hoangan on 27 November 2007 - 06:18 PM in Mathematics

Pls, help me these 2 questions



1. y = (lnx)^(√x) , dy/dx ?


2. y= sin2 (x) / (1+cotg x) + cos2 (x) / (1+tan x) , dy/dx = ?



#100567 how do you integrate...

Posted by cK_hoangan on 27 November 2007 - 06:01 PM in Mathematics

It isnít too bad.

Let rearrange it first

1/(1+cosx) = 1/( 1 + 2cos2(x/2)-1) cosx = 2cos2 (x/2)-1
= 1/ 2 cos2 (x/2)
=1/2 sec2 (x/2)

From now, if I werenít wrong, integrate sec2 (x/2), we get tan (x/2) + C !!!

So the answer is 1/2 tan (x/2) + C