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#100885 Differentiation Help

Posted by mikey4020 on 17 March 2008 - 08:42 PM in Mathematics

Makes sense now, I was trying to use Product Rule and everything. laugh.gif



#100883 Differentiation Help

Posted by mikey4020 on 17 March 2008 - 07:30 PM in Mathematics

Wondering if anyone can give us a hand with this question?

f(x)=exp(sin2x)

It's the exp bit that's confusing me mad.gif



#100490 NAB Question

Posted by mikey4020 on 01 November 2007 - 03:40 PM in Chemistry

I've got a question here from a practice NAB that's bothering me somewhat and I'm hoping someone can shed some light!

If 10ml of hydrogen is reacted with 10ml of propene, the volume of the resulting gas will be
A 5ml
B 0ml
C 10ml
D 20ml




#100465 Help with HW Question

Posted by mikey4020 on 22 October 2007 - 11:25 AM in Mathematics

Thank, can't believe I never got that, it's fairly simple if you spot the important things at the start!!



#100453 Help with HW Question

Posted by mikey4020 on 21 October 2007 - 02:05 PM in Mathematics

I wonder if anyone can give me a hand with this question, it's been sticking me for a while now.

Show that 

\begin{align*}f'(x)=2\sec x\end{align*}

for 

\begin{align*}f(x)=\ln (\frac{1+\sin x}{1-\sin x})\end{align*}

thanks smile.gif



#97904 Physics' Post Mortem

Posted by mikey4020 on 17 May 2007 - 03:34 PM in Physics

How do you get the 8V? I ended up with 4.8 or something!



#97881 Physics' Post Mortem

Posted by mikey4020 on 17 May 2007 - 01:00 PM in Physics

I've dropped a few silly marks in the "multiple guess" questions but hopefully I've got about 12 right at least because I never do well in multiple choice! I was really glad there was no questions in the multi-choice that give you three statements and then ask you which is true!!

I felt the written went OK though I messed up Q21 though forgot direction at part (d) and (a) physics teacher nearly hit me lol

Also can someone tell me what the voltage on the graph should have been in Q25 [c]



#97578 Ready for exam?

Posted by mikey4020 on 15 May 2007 - 03:00 PM in Physics

I'd love to have SG Physics back, two marks for stating what a laser was an abbreviation for or three marks for plugging data into an equation, those were the days. blink.gif



#97557 Ready for exam?

Posted by mikey4020 on 15 May 2007 - 01:43 PM in Physics

I'm really annoyed about Physics being the day after Maths stupid SQA do they even read the timetable? mad.gif mad.gif



#97555 Exam Post Mortem

Posted by mikey4020 on 15 May 2007 - 01:39 PM in Mathematics

I think my in Paper 1 I did really well, except from the graph at the end and I did something terrible in question 6 so no marks there I don't think, well maybe 1 or 2! As for Paper 2, what a nightmare! I can't even look at the solutions for that!

For the vector one in Paper 2 the one about the cube I got 30 degree.gif also.

I'm don't know what to expect now but hopefully I've done enough for at least a B! We shall see!



#97388 Ready?

Posted by mikey4020 on 14 May 2007 - 06:05 PM in Mathematics

I'm a it nervous about tomorrow, done quite a lot of preparation in the lead up and did a couple of hours today. Will probably just go over silly stuff tonight like exact values, and all my cos and sin replacements!! unsure.gif Well good luck everyone!



#97330 Free Multiple-Choice Test

Posted by mikey4020 on 14 May 2007 - 11:51 AM in Mathematics

Woops that was rather embarrassing!! Least I've learned something lol. I agree that whilst logs are only a small part of the course I didn't feel they were covered that well in my school they kind of left it to the last minute.



#97326 Free Multiple-Choice Test

Posted by mikey4020 on 14 May 2007 - 11:22 AM in Mathematics

This is how I done it but I don't know if it's right. Using the point (4,18) you substitute 18 for y and 4 for x. 18=3e^4^k then you take log_{e} of both sides to give you, log_{e}18=4klog_{e}3 Then rearange to give 4k=log_e18-log_e3 After subtracting the left hand side you get log_e15 take the 4 from the 4k over and divide to give k=\frac{log_e15}{4} which is the same as k=\frac{1}{4} log_e15 and hence answer C

Hope that helps, took me ages to do using that LaTex stuff laugh.gif

IGNORE ABOVE: Where I said you take it over and subtract you don't you take it over and divide and this means that you take 3 away from 18 to give you log_e15 the rest shoudl still be valid! rolleyes.gif



#97323 Free Multiple-Choice Test

Posted by mikey4020 on 14 May 2007 - 11:06 AM in Mathematics

Yeah that's a bit better I think I've got it now. The answers I got are B & C respectively.



#97317 Free Multiple-Choice Test

Posted by mikey4020 on 14 May 2007 - 09:41 AM in Mathematics

These were really useful, highlighted a few isuues to correct. I got Q5 wrong in Test B and I don't know how to get it any chance you could explain it for me. Also could you explain Q10 in test B because I got the answer and I don't know how.



#97287 Free Multiple-Choice Test

Posted by mikey4020 on 13 May 2007 - 08:40 PM in Mathematics

I tried to do this like a couple of questions at a time and now it looks like I've got a really rubbish score lol! crying.gif blush.gif



#96936 what are you doing for the main exam?

Posted by mikey4020 on 10 May 2007 - 06:30 PM in English

I'm hoping for

Drama: Macbeth
Poetry: My Last Duchess or Valentine

I've also got The Great Gatsby which I'll do if my back's really to the wall and I've got a rescue text, The Telegram as a last ditch attempt. Also got a few more poems by Carol Anne Duffy. Hoping I'll be able to fit something together and pick up a lot of the marks in the close reading.



#95598 Help with a Question!

Posted by mikey4020 on 04 April 2007 - 10:18 PM in Mathematics

Yeah thanks a lot I've got it now!! rolleyes.gif



#95597 Help with a Question!

Posted by mikey4020 on 04 April 2007 - 10:14 PM in Mathematics

Yes I see where to go, I have used synthetic devision so that I have 1 4 & 0 along the bottom of the table. Now I know the 0 signifies that x+1 is a factor but I'm a but uncertain as to where to get the other factor from.



#95541 Help with a Question!

Posted by mikey4020 on 04 April 2007 - 11:44 AM in Mathematics

Sorry but this one is really bugging me and I was wondering if anyone can give some help.

I've cut all the usual rubbish about the context of the question out to make it easier to type.

Curve PQ has equation \\y=3x^2-x^3 . The line PQ is horizontal.

The \\x-coordinates of P and Q are -1 and a respectively.

(a) Show clearly that the equation of the line PQ is \\y=4 (Done this part OK)

(b) Hence determine the value of a

It is part b I am having problems with, I thought that using part (a) I could substitute a in to get the polynomial \\3a^2-a^3-4 and then go through the process to solve it and get the second root which would be a. I can't get this to work however and therefore I' hoping someone will help me with this.

There is a graph which I've done roughly below. Apologies for the bad drawing.



Thanks!!