**3( b )**on

**Paper 2**is

(-2,-11).

I get

**(-2,-11)**but they get

**(-2,11)**.

Which 1's right?

Started by sparky, Apr 15 2004 08:54 PM

63 replies to this topic

Posted 19 April 2004 - 11:42 AM

Could someone have a look at this Specimen Question Paper and tell me whether the answer to **3( b )** on **Paper 2 ** is

(-2,-11).

I get**(-2,-11)** but they get **(-2,11)**.

Which 1's right?

(-2,-11).

I get

Which 1's right?

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Posted 19 April 2004 - 11:47 AM

OK then.

Maybe not.

I had the the other SQP but on this 1 they seem to have included only Paper 1, so if anyone has downloaded the 1 I'm talking about before could they tell me the answer.

Quite confusing!

Maybe not.

I had the the other SQP but on this 1 they seem to have included only Paper 1, so if anyone has downloaded the 1 I'm talking about before could they tell me the answer.

Quite confusing!

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Posted 19 April 2004 - 01:10 PM

The answer's (-2,-11), theyve made a misprint there

That paper was in the Leckie and Leckie Past Paper Book a couple of years ago and theyve got (-2,-11)

That paper was in the Leckie and Leckie Past Paper Book a couple of years ago and theyve got (-2,-11)

Posted 19 April 2004 - 05:31 PM

QUOTE (sparky @ Apr 17 2004, 01:55 PM) |

9 ( B ) i got cos THETA to be a negative, which would mean 2 answers, anyone else get this? |

For these questions do you not just usually take the answer which appears in the calculator.

Do you have to use the CAST diagram? I haven't came across a question yet in which you do actually have to use it.

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Posted 19 April 2004 - 05:40 PM

QUOTE (Allan @ Apr 17 2004, 02:23 PM) |

Then to find the radius of the circle you can use the distance formula to find the length of QC, which is the radius. CQ = √(1-1)² + (9-4)² CQ = √(0)² + (5)² CQ = √25 CQ = 5 |

For this can you not just takeaway 4 from 9 as it is a vertical line.

Anyway, I was wondering if you could tell me how to work out the co-ordinates of T. Its probably really really simple just that I am too stupid to notice!!!

I get the tangent to be

(-9,9)?

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Posted 19 April 2004 - 07:04 PM

QUOTE (ally @ Apr 19 2004, 06:40 PM) |

For this can you not just takeaway 4 from 9 as it is a vertical line. |

That would be just as valid, and would be easier and save time lol

Posted 19 April 2004 - 11:07 PM

Yes we all like things taht save time lol. Ok everyone night night. Notice the time on my post- 00:10 . I finished english homework 10 mins ago when I started at 7 . Thats how much I get. Thats why I have no time for Maths and am really thick at it.

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Posted 20 April 2004 - 05:46 PM

QUOTE (sparky @ Apr 15 2004, 09:54 PM) |

And any tips on question 7, is there an easy way of working out the co-ordinates you need, I mean it only is worth 3 marks. |

Dunno if ur still stuck on this question but...

the vector VK can be found by adding the vectors VA, AB and BK together

so VK = VA + AB + BK

vector BC is the same as vecotr AD which ur given in the question; using the section formula you should be able to work out BK

I get BK as

2

-1

1

So adding vA and AB and BK should work out at

1

-8

-16

which is VK

Posted 20 April 2004 - 05:59 PM

I know a short way to do that as well.My class have short ways of doing everything- like the vector division of a line short rule

The rule for parabolas

Log cycle

We have short rules for a lot of stuff! If anyone gets really really confused about all a load of working and want a short rule for something ask me!

The rule for parabolas

Log cycle

We have short rules for a lot of stuff! If anyone gets really really confused about all a load of working and want a short rule for something ask me!

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Posted 20 April 2004 - 08:00 PM

Yeah we are going over that vectors q's 2moro, since our class text *Maths In Action*, didn't have any examples like it in it.

Thanks anyway!

Thanks anyway!

Mark

Posted 20 April 2004 - 10:04 PM

QUOTE (Allan @ Apr 15 2004, 09:03 PM) |

You can complete the square of the radius² giving 5(k + 1/10)² + 1(19/20) |

Another shortcut, , for this question is to use the discriminant which will give a negative answer, i.e no real roots.

I like my shortcuts!!!

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Posted 20 April 2004 - 10:07 PM

QUOTE (Steve @ Apr 17 2004, 02:47 PM) |

Here's the working for question 6 |

Another shortcut...

...Well I think so anyway, you may not!!

Instead of using the nature table I use the 2nd differential form which you may or may not be familiar with. It gives the same answer, may not be easier at first , but once you get the hang of it saves time and is really easy.

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Posted 21 April 2004 - 09:01 PM

Yeh i know there is more than one differential form but which one is the second?

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Posted 25 April 2004 - 11:26 AM

Yeah the second differentiation is just differentiating the result of the original differentiation.

I hope I haven't confused you with all the 'differentiations'.

I hope I haven't confused you with all the 'differentiations'.

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Posted 25 April 2004 - 01:56 PM

Nope its intregration that confuses me! So see if something was differentiated then the answer differentiated would you integrate it and then integrate that answer to get back to the original equation?

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Posted 25 April 2004 - 03:32 PM

Really I would stick to the nature table! For all the 5mins it takes to do! Unless you have been taught this method and are confident with it! Its not even in the higher syallbus, I think this comes under advanced higher!

Mark

Posted 25 April 2004 - 09:53 PM

QUOTE (LouiseMurphy @ Apr 25 2004, 01:56 PM) |

So see if something was differentiated then the answer differentiated would you integrate it and then integrate that answer to get back to the original equation? |

It should do. I think that you would just ignore the 'Constant' here. I haven't really thought about it though. Anyway, why would you want to do that?

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Posted 26 April 2004 - 02:44 AM

Yes, the second derivative test is another method for determining the nature of stationary points. It is covered in the AH course, though I personally find nature tables OK (especially with a graphics calculator!)

Posted 29 April 2004 - 10:06 PM

Could someone please help me with **Q11** on the **Higher Winter Paper 2002 Paper 1 ** as I'm totally stuck with that one.

Help would be appreciated.

Thanks

Help would be appreciated.

Thanks

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Posted 30 April 2004 - 06:26 PM

If only i had the past papers with me.

I'll reply again on sunday with the solution. I would tomorrow, but i'm extremely busy.

I'll reply again on sunday with the solution. I would tomorrow, but i'm extremely busy.

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