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Paper 2 2005 - HSN forum

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Paper 2 2005


3 replies to this topic

#1 laura_lou92

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Posted 20 May 2009 - 02:52 PM

not entirely sure what to do... anyone thing they could help?

log4(5-x) - log4(3-x) = 2 x<3


#2 Philip

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Posted 20 May 2009 - 03:15 PM

QUOTE (laura_lou92 @ May 20 2009, 03:52 PM) <{POST_SNAPBACK}>
not entirely sure what to do... anyone thing they could help?

log4(5-x) - log4(3-x) = 2 x<3


Haha i just did this one 5 minutes ago laugh.gif

Right, you already know log_{4}(5-x)-log_{4}(3-x)=2

So you re-arrange to log_{4}(5-x)-log_{4}(3-x)=log_{4}4^2 Remember : log_{4}4=1

Then you can cancel out the logs:

(5-x)/(3-x)=4^2

16(3-x)=(5-x)

48-16x=5-x

5-15x=48

-15x=43

x=-43/15


Hope this helped! Any questions just reply back.


Yeah!

#3 laura_lou92

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Posted 20 May 2009 - 03:40 PM

QUOTE (Philip @ May 20 2009, 04:15 PM) <{POST_SNAPBACK}>
QUOTE (laura_lou92 @ May 20 2009, 03:52 PM) <{POST_SNAPBACK}>
not entirely sure what to do... anyone thing they could help?

log4(5-x) - log4(3-x) = 2 x<3


Haha i just did this one 5 minutes ago laugh.gif

Right, you already know log_{4}(5-x)-log_{4}(3-x)=2

So you re-arrange to log_{4}(5-x)-log_{4}(3-x)=log_{4}4^2 Remember : log_{4}4=1

Then you can cancel out the logs:

(5-x)/(3-x)=4^2

16(3-x)=(5-x)

48-16x=5-x

5-15x=48

-15x=43

x=-43/15


Hope this helped! Any questions just reply back.





#4 laura_lou92

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Posted 20 May 2009 - 03:44 PM

QUOTE (laura_lou92 @ May 20 2009, 04:40 PM) <{POST_SNAPBACK}>
QUOTE (Philip @ May 20 2009, 04:15 PM) <{POST_SNAPBACK}>
QUOTE (laura_lou92 @ May 20 2009, 03:52 PM) <{POST_SNAPBACK}>
not entirely sure what to do... anyone thing they could help?

log4(5-x) - log4(3-x) = 2 x<3


Haha i just did this one 5 minutes ago laugh.gif

Right, you already know log_{4}(5-x)-log_{4}(3-x)=2

So you re-arrange to log_{4}(5-x)-log_{4}(3-x)=log_{4}4^2 Remember : log_{4}4=1

Then you can cancel out the logs:

(5-x)/(3-x)=4^2

16(3-x)=(5-x)

48-16x=5-x

5-15x=48

-15x=43

x=-43/15


Hope this helped! Any questions just reply back.



Thank u so much =)





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