Jump to content


Roots of complex numbers


2 replies to this topic

#1 HeatherL

    Showing Improvement

  • Members
  • PipPip
  • 10 posts
  • Gender:Female

Posted 19 May 2009 - 08:52 AM

Hi!!
Could somebody pleeeeeease help me with this question....
Solve the equation z power3.gif = 8
Normally i'm fine with this type of question but this one just stumped me and i'm starting to panic unsure.gif ermm.gif
Thanks,
Heather biggrin.gif

#2 Marcus

    Site Swot

  • Members
  • PipPipPipPip
  • 147 posts
  • Location:Aberdeen
  • Interests:Guitar - Passed my grade 6 :D :D<br />Write computer programs - won Heriot-Watt programming challenge 2006 and 2007 :D<br />
  • Gender:Male

Posted 19 May 2009 - 02:17 PM

rearrange into z³-8=0, now from this you can see the z=2 must be a solution, (as sticking z=2 makes the equation true)

so synthetic division (or long division if you want to waste time biggrin.gif)
CODE
   |1   0   0  -8
2  |    2   4   8
   |_______________
    1   2   4   0


so z³-8=(z-2)(z²+2z+4)
so we need the roots of the quadratic biggrin.gif, back to good 'al quadratic formula

a=1,b=2,c=4

Working
so the solutions are z=2, 1+i sqrt.gif 3 , 1-i sqrt.gif 3
=-=-=Marcus=-=-=

#3 HeatherL

    Showing Improvement

  • Members
  • PipPip
  • 10 posts
  • Gender:Female

Posted 20 May 2009 - 09:36 AM

ooooo I get it now rolleyes.gif !!!thanks!!!!!!!!
Heather biggrin.gif






1 user(s) are reading this topic

0 members, 1 guests, 0 anonymous users