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2008 - Paper 2 - Question 1c - HSN forum

# 2008 - Paper 2 - Question 1c

### #1christie

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Posted 18 May 2009 - 12:16 PM

Find the co-ordinates of the point of intersection of the perpendicular bisector of BC and the median from C.

From a) and b) i have the equations...

y = 2x-5 (perp bisector BC)
y = -3x+10 (median C)

I done simultaneous equations but got y=5 and x=5, the answer says the point should be (3,1).

Both equations are correct but i dont know how you get the answer from there, anyone know how to do it?

Thanks x

### #2Marcus

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Posted 18 May 2009 - 09:03 PM

You must have solved the sim eqns wrong

should be
y=2x-5
y=-3x+10

so 2x-5=-3x+10
5x=15
x=3

y=(2)(3)-5
y=1

hope this helps
=-=-=Marcus=-=-=

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