Find the co-ordinates of the point of intersection of the perpendicular bisector of BC and the median from C.
From a) and b) i have the equations...
y = 2x-5 (perp bisector BC)
y = -3x+10 (median C)
I done simultaneous equations but got y=5 and x=5, the answer says the point should be (3,1).
Both equations are correct but i dont know how you get the answer from there, anyone know how to do it?
Thanks x
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2008 - Paper 2 - Question 1c
Started by christie, May 18 2009 12:16 PM
1 reply to this topic
#2
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Posted 18 May 2009 - 09:03 PM
You must have solved the sim eqns wrong
should be
y=2x-5
y=-3x+10
so 2x-5=-3x+10
5x=15
x=3
y=(2)(3)-5
y=1
hope this helps
should be
y=2x-5
y=-3x+10
so 2x-5=-3x+10
5x=15
x=3
y=(2)(3)-5
y=1
hope this helps
=-=-=Marcus=-=-=
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