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2006 paper II Q10(b) - HSN forum

2006 paper II Q10(b)

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#1Ron90

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Posted 16 May 2008 - 03:50 PM

Im stuck on this question.

Ive looked at a solution to it and it goes like this:

25cos(x-1.29) = 1

then to

x = + 1.29

im confused how this is done. Any help?

#2Marcus

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Posted 16 May 2008 - 03:59 PM

and are inverse functions of each other, ie

y = can be changed to x = and vice versa
you started with

divide through by 25

take inverse cosines of both sides ie, use the rule above

then move the 1.29 to the other side

hope this helps
=-=-=Marcus=-=-=

#3Ron90

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Posted 16 May 2008 - 04:02 PM

QUOTE(Marcus @ May 16 2008, 04:59 PM)
and are inverse functions of each other, ie

y = can be changed to x = and vice versa
you started with

divide through by 25

take inverse cosines of both sides ie, use the rule above

then move the 1.29 to the other side

hope this helps

Brilliant. Get it now thanks

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