**Polynomals - Non Calc Q -5**

Given that (x-2) and (x+3) are factors of f(x) = 3x

^{3}+2x

^{2}+cx+d find the values of c and d.

__working so far:__

2|3 2 c d

6 16 16+2c

______________

3 8 16+c 16+2c+d

-3|3 2 c d

-9 21 -63-3c

________________

3 -7 21+c -63-3c+d

Using simultaimous eq.

32+2c+d =0

and

-63-3c+d=0

Therefore:

-32=2c+d

63=-3c+d

thats where I got stuck...can't really see where I've messed up in the question and I don't really know where to go from there

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**Functions - 2002 Winter Diet Q - 9**

a] The function f, is defined on a suitable domain, is given by f(x) = 3/(x+1) find an expression for h(x) = (f(fx)) giving your answer as a fraction in the simplest form.

__working so far__

f(x) = 3/(x+1)

h(x) = f(f(x))

h(x) = 3/(3/x+1)+1

I worked it though every way I could think of and even though the answers say 3(x+1)/(x+4) I don't see how on earth to get that.

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**Functions - 2002 Winter Diet Q - 10**

A function f is defined by f(x) = 2x+3+(18/(x-4) where x is no equal to 4. Find the values of x for which the funtion is increasing.

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Thank to anyone who tries to help, I know its a lot but my prelims in like 2 weeks and I just go tmy uni offers though and I wanna try and avoid the screams of help echoing though the forum that I caused last year.

xo