SOMETHING = NOTHING, it's possible !!! Let see the magic of Maths now :

Consider :

S = 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 +.....

=> 1/2 S = 1/4 + 1/6 + 1/8 + .....

=>S - 1/2S = 1/2 + 1/3 + 1/5 + 1/7 + .... (canceled respectly 1/4; 1/6; 1/8; ... from S by 1/2 S)

=> 1/2 S = 1/2 + 1/3 + 1/5 + 1/7 + ...

Now we subtract the second 1/2 S for the first 1/2 S :

1/2 S - 1/2 S = (1/2 + 1/3 + 1/5 + 1/7 + ... ) - ( 1/4 + 1/6 + 1/8 + ... )

1/2 S - 1/2 S = 1/2 + 1/3 + 1/5 + 1/7 + ... - 1/4 - 1/6 - 1/8 - ...

0 = 1/2 + ( 1/3 - 1/4) + ( 1/5 - 1/6) + ( 1/7 - 1/8 ) + ....

0 = 1/2 + 1/12 + 1/30 + 1/56 + ....

From now. obviously seeing that the right hand side would end up with a positive number which (of course) is greater than 0 . But on the left hand side, so funny, it's definetly 0. ( what else can be if subtract 1/2 S by itself ? )

So, can u now get the point ? Clearly, NOTHING = SOMETHING , MATHS is miracle !!!!

**0**

# Who belives SOMETHING = NOTHING ?

Started by cK_hoangan, Nov 29 2007 02:04 PM

3 replies to this topic

### #1

Posted 29 November 2007 - 02:04 PM

### #2

Posted 06 January 2008 - 01:07 AM

That puzzled me for quite a while, the problem is that your S changes its value, you have got an infinite series...but the number of terms you specify it to changes, therefore changing the value...

keeping it to 3 terms

if S = 1/2 + 1/3 +1/4

then 1/2S = 1/4 + 1/6 + 1/8 = 13/24

S-1/2S = 1/2 + 1/3 +1/4 - 1/4 - 1/6 - 1/8

1/2S= 1/2 + 1/3 - 1/6 - 1/8 = 13/24

therefore if you subtracted the first 1/2S from the second 1/2S you would get 0 = 0

QED

keeping it to 3 terms

if S = 1/2 + 1/3 +1/4

then 1/2S = 1/4 + 1/6 + 1/8 = 13/24

S-1/2S = 1/2 + 1/3 +1/4 - 1/4 - 1/6 - 1/8

1/2S= 1/2 + 1/3 - 1/6 - 1/8 = 13/24

therefore if you subtracted the first 1/2S from the second 1/2S you would get 0 = 0

QED

**=-=-=Marcus=-=-=**### #3

Posted 17 January 2008 - 03:47 PM

but ... then, wat is the error ?

If you agree that it is an infinite serie, how could you know the number of its terms is changed ?

If you agree that it is an infinite serie, how could you know the number of its terms is changed ?

### #4

Posted 20 January 2008 - 01:57 AM

but ... then, wat is the error ?

If you agree that it is an infinite serie, how could you know the number of its terms is changed ?

If you agree that it is an infinite serie, how could you know the number of its terms is changed ?

the problem is: you have solved an infinite series using a set number of terms, your S , and both s are all to different numbers of terms, it is the differences in these numbers of terms that the error arises...

To do this properly you would have to specify S in such a way that it can be infinite, ie S equals the recurrence relation:

which you half:

then you subtract them:

now you should be able to see that if you subtract the two s now you would get

**=-=-=Marcus=-=-=**#### 1 user(s) are reading this topic

0 members, 1 guests, 0 anonymous users