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1 + 1 = 1 ? ? ? - HSN forum 1 + 1 = 1 ? ? ?

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#1cK_hoangan

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Posted 28 November 2007 - 10:29 PM

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... #2Jammie1000000

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Posted 29 November 2007 - 01:31 PM

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... (A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0 #3cK_hoangan

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Posted 29 November 2007 - 01:45 PM

Well-done !!!! as I said, it's all for relaxing : D

You wanna try once more with 1 > 4 ? I will prove it soon #4Marcus

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Posted 06 January 2008 - 04:01 PM

just to go along the same lines of posting bizarre mathematics, here is a proof that or in fact any number you want eqn 1) x+1 = 0
eqn 2) 2x+2 = 0

divide eqn 2 by eqn 1 cancel the x+1 on top and bottom to get: but this = anything helps prove the above problem...

=> (A-B)(A+B)= B (A-B) , (A-B) = 0
=> 0(A+B)= 0B
=>2B = B
so if =2
then this works XD XD
=-=-=Marcus=-=-=

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Posted 07 January 2008 - 07:44 PM

Here's a tough one (you'll need to have done complex numbers, can't remember when it comes up in advanced higher): Where's the error?

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#6Marcus

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Posted 10 January 2008 - 11:43 PM

Right I don't think this is correct but: and also is usually written as as angles usually lie between and so when you multiplied the by you were effectively multiplying by which you can't do.

Am i even remotely on the right lines here? =-=-=Marcus=-=-=

#7englisher

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Posted 21 February 2008 - 02:55 PM

Here's a tough one (you'll need to have done complex numbers, can't remember when it comes up in advanced higher): Where's the error?

Can't put brackets round e^2ipi ?

#8Marcus

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Posted 22 February 2008 - 09:16 PM

Can't put brackets round e^2ipi ?

I wish it was as simple as that, but yeah you can... one of the rules of indices in the case of a would be and b would be =-=-=Marcus=-=-=

#9Wildespleen

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Posted 21 January 2009 - 08:13 PM

Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).
I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

#10Marcus

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Posted 27 January 2009 - 02:12 PM

QUOTE (Wildespleen @ Jan 21 2009, 08:13 PM) <{POST_SNAPBACK}>
Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).
I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

Yeah , and it comes from Euler's formula: (only briefly mentioned in AH) I had to ask my uni profs to explain what is wrong with this proof...
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#11Monkey Man

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Posted 02 January 2010 - 06:50 PM

QUOTE Jammie1000000
QUOTE(cK_hoangan @ Nov 28 2007, 10:29 PM) View Post
This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B
=> A^2 = AB (multiply both by A)
=> A^2 - B^2 = AB - B^2 (take away both to B^2)
=> (A-B)(A+B)= B (A-B)
=> A+B = B
=> 2B = B (hence A = B)
=> 2 = 1
=> 1 + 1 = 1 blink.gif BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... tongue.gif

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

cool.gif

can i just add that this is not dividing through by (A-B), they cancel each other out  #12Marcus

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Posted 27 January 2010 - 05:37 PM

but they cancel out, because you are dividing through by (a-b) << that the operation you are actually doing when you cancel out terms
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