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# 1 + 1 = 1 ? ? ?

Started by cK_hoangan, Nov 28 2007 10:29 PM

11 replies to this topic

### #1

Posted 28 November 2007 - 10:29 PM

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=> (A-B)(A+B)= B (A-B)

=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=> (A-B)(A+B)= B (A-B)

=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

### #2

Posted 29 November 2007 - 01:31 PM

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=>

=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=>

**(A-B)(A+B)**= B (A-B)=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ...

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

### #3

Posted 29 November 2007 - 01:45 PM

Well-done !!!!

as I said, it's all for relaxing : D

You wanna try once more with 1 > 4 ? I will prove it soon

as I said, it's all for relaxing : D

You wanna try once more with 1 > 4 ? I will prove it soon

### #4

Posted 06 January 2008 - 04:01 PM

just to go along the same lines of posting bizarre mathematics, here is a proof that or in fact any number you want

eqn 1) x+1 = 0

eqn 2) 2x+2 = 0

divide eqn 2 by eqn 1

cancel the x+1 on top and bottom to get:

but this = anything helps prove the above problem...

=> (A-B)(A+B)= B (A-B) , (A-B) = 0

=> 0(A+B)= 0B

=>2B = B

so if =2

then this works XD XD

eqn 1) x+1 = 0

eqn 2) 2x+2 = 0

divide eqn 2 by eqn 1

cancel the x+1 on top and bottom to get:

but this = anything helps prove the above problem...

=> (A-B)(A+B)= B (A-B) , (A-B) = 0

=> 0(A+B)= 0B

=>2B = B

so if =2

then this works XD XD

**=-=-=Marcus=-=-=**### #5

Posted 07 January 2008 - 07:44 PM

Here's a tough one (you'll need to have done complex numbers, can't remember when it comes up in advanced higher):

Where's the error?

Where's the error?

HMFC - Founded 1874, beefing the Cabbage since 1875

### #6

Posted 10 January 2008 - 11:43 PM

Right I don't think this is correct but:

and also is usually written as as angles usually lie between and

so when you multiplied the by you were effectively multiplying by which you can't do.

Am i even remotely on the right lines here?

and also is usually written as as angles usually lie between and

so when you multiplied the by you were effectively multiplying by which you can't do.

Am i even remotely on the right lines here?

**=-=-=Marcus=-=-=**### #9

Posted 21 January 2009 - 08:13 PM

Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).

I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

### #10

Posted 27 January 2009 - 02:12 PM

QUOTE (Wildespleen @ Jan 21 2009, 08:13 PM) <{POST_SNAPBACK}>

Can I just confirm that e^2ipi is indeed one? I presume it originates from 'e^ipi + 1 = 0'? (Which we haven't really covered in class so far, we only mentioned it).

I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

I've puzzled over this one for a while now and the only real possible fault I, personally, can find is this. Failing that, I fear the textbooks will have to be rewritten-> 1+1=1 and 2+2=2! There'll be anarchy in the streets! XD

Yeah , and it comes from Euler's formula: (only briefly mentioned in AH)

I had to ask my uni profs to explain what is wrong with this proof...

**=-=-=Marcus=-=-=**### #11

Posted 02 January 2010 - 06:50 PM

QUOTE Jammie1000000

QUOTE(cK_hoangan @ Nov 28 2007, 10:29 PM) View Post

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=> (A-B)(A+B)= B (A-B)

=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 blink.gif BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... tongue.gif

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

cool.gif

can i just add that this is not dividing through by (A-B), they cancel each other out

QUOTE(cK_hoangan @ Nov 28 2007, 10:29 PM) View Post

This is a "trick stuff" in Maths which quite interesting. Hope that anyone will enjoy it.

Assume : A = B

=> A^2 = AB (multiply both by A)

=> A^2 - B^2 = AB - B^2 (take away both to B^2)

=> (A-B)(A+B)= B (A-B)

=> A+B = B

=> 2B = B (hence A = B)

=> 2 = 1

=> 1 + 1 = 1 blink.gif BINGO !!!

I think we shouldn't study Maths anymore cause It's all wrong now ... tongue.gif

(A-B)=0 so you cannot divide through by (A-B) as you cannot divide by 0

cool.gif

can i just add that this is not dividing through by (A-B), they cancel each other out

### #12

Posted 27 January 2010 - 05:37 PM

but they cancel out, because you are dividing through by (a-b) << that the operation you are actually doing when you cancel out terms

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