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log problem


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#1 stuck

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Posted 08 March 2007 - 09:48 PM

"show by solving the following log equation that the exact value of x can be written in the form 4p root p and write down the value of p.

log to the base x (2x) + 2log to the base x of 8 =3"

I started by doing:
log to the base x (2x *64) = 3
log to the base x (128x) = 3


and after that im not really sure... any help appreciated





#2 Nathan

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Posted 09 March 2007 - 06:24 AM

Bit of a starter for you;

logx2x + logx8 = 3

so, by the logxa + logxb = logxab, ( http://www.hsn.uk.net/files/HSN23300.pdf , page 4 [136] )

logx2x + logx8 = 3
is equivalent to logx16x = 3





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