Show that cos(pi/2 + x) = -sinx
Can anyone Help?
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ANOTHER homework question
Started by craig1e, Jan 09 2007 08:26 PM
2 replies to this topic
#2
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Fully Fledged Genius
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Posted 09 January 2007 - 09:10 PM
cos(
/2 + x) = cos[pi]/2.cosx - sin[pi]/2.sinx
=0.cosx - 1.sinx
=sinx
(This is just taking advantage of the fact that cos(a+b) = cosacosb - sinasinb
)
/2 + x) = cos[pi]/2.cosx - sin[pi]/2.sinx=0.cosx - 1.sinx
=sinx
(This is just taking advantage of the fact that cos(a+b) = cosacosb - sinasinb
)
#3
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Posted 09 January 2007 - 09:27 PM
cheers mate. All so simple now 
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