Posted 19 December 2006 - 09:00 PM
ln(1 + x/1 - x)
Posted 19 December 2006 - 09:36 PM
Let , so you have . You can differentiate y with repsect to x using the chain rule now. Note that you will probably use the quotient rule to differentiate u with respect to x.
Posted 20 December 2006 - 12:10 PM
(exclude the u, this is just cause I'm too lazy to rewrite the expression)
to 1/(1-x) which makes it a pretty straightforward integral, ln[1/(1-x)]
ps: ad_absurdum hope you don't mind me nicking your tex.
edit: sorry I'm pretty sure I read it was an integral question! Anyway you still could simplify and use the chain rule.
Posted 20 December 2006 - 08:19 PM
Posted 20 December 2006 - 11:39 PM
that differentiates to:
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