Given the gradient and finding the equation?
Posted 15 November 2006 - 08:51 PM
Given its gradient, find the equation of the tangent to this parabola.
y= x squared, m = 2 ?
Im completely lost but when I do b squared - 4ac i get a = 1, b= -2 and c = -1. Could this be where I am going wrong?
The answer in the book is y = 2x - 1. How do they get this?
Posted 15 November 2006 - 08:56 PM
So do that, you know that dy/dx = 2 so find what dy/dx is and solve it for 2.
So after that you have the x co-ordinate, plug that into the equation of the curve and use the answer from that for the y co-ordinate.
After that use the formula y-b=m(x-a)
Does that make any sense to you?
Posted 15 November 2006 - 09:06 PM
Posted 15 November 2006 - 09:55 PM
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