1.
3logax-logax-logaz
=logax3-logax-logaz
=loga(x3/y/z)
where do I go from there?
is it
=loga(x3z/y) or not?
2.
log2(x+1) - log2x = 3
how do you do that one?
god...I hate maths!! lol
0
2 questions about logs
Started by Nathan, Oct 08 2006 08:25 PM
2 replies to this topic
#1
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Posted 08 October 2006 - 08:25 PM
#2
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Posted 08 October 2006 - 08:38 PM
You're making the first one more complicated than it is 
.
I'm assuming you've just to simplify the expression. You've got
but this is just 
. This should make it simpler.
For the second one, I assume you've to solve for x. You can combine the LHS into a single log term then put into exponential form using the rule
. I get 
, if you're interested.
I know you won't want to, because you'll feel like a school pupil again, but you could always have a look at the Higher Logarithms notes!
.I'm assuming you've just to simplify the expression. You've got
but this is just . This should make it simpler.For the second one, I assume you've to solve for x. You can combine the LHS into a single log term then put into exponential form using the rule
. I get , if you're interested.I know you won't want to, because you'll feel like a school pupil again, but you could always have a look at the Higher Logarithms notes!
#3
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Posted 08 October 2006 - 08:40 PM
Thank you 
lol...thanks
QUOTE
I know you won't want to, because you'll feel like a school pupil again, but you could always have a look at the Higher Logarithms notes!
lol...thanks
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