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2 questions about logs - HSN forum

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2 questions about logs


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#1 Nathan

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Posted 08 October 2006 - 08:25 PM

1.
3logax-logax-logaz
=logax3-logax-logaz
=loga(x3/y/z)

where do I go from there?

is it

=loga(x3z/y) or not?

2.
log2(x+1) - log2x = 3

how do you do that one?

god...I hate maths!! lol


#2 Steve

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Posted 08 October 2006 - 08:38 PM

You're making the first one more complicated than it is tongue.gif.

I'm assuming you've just to simplify the expression. You've got 3\log_ax-\log_ax but this is just 2\log_ax. This should make it simpler.

For the second one, I assume you've to solve for x. You can combine the LHS into a single log term then put into exponential form using the rule x=a^y\iff y=\log_ax. I get \frac17, if you're interested.

I know you won't want to, because you'll feel like a school pupil again, but you could always have a look at the Higher Logarithms notes!
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#3 Nathan

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Posted 08 October 2006 - 08:40 PM

Thank you smile.gif

QUOTE
I know you won't want to, because you'll feel like a school pupil again, but you could always have a look at the Higher Logarithms notes!


lol...thanks tongue.gif







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