Stupid question = do you lose marks for not doing graphs on the graph paper provided?

whose drawing a graph?

i drew a few squiggly lines

Started by albidalbibab, May 19 2006 02:52 PM

153 replies to this topic

Posted 19 May 2006 - 05:54 PM

did anyone get z=0 for the gauss elimination.

Nothing!!!!!!!!

Posted 19 May 2006 - 05:58 PM

who got T=40 for Q10

Nothing!!!!!!!!

Posted 19 May 2006 - 05:58 PM

When you get to a certain stage it was like 3(k^2+k) or sth anyway you have to do another proof that k^2+k is divisible by 2, then it works

k^2 + k = k(k+1)

that's two consecutive integers, so one of them is even, so teh whole expression is even. Or you can consider cases of odd and even (i.e. let k=2n and then k=2n+1) and show it that way.

Posted 19 May 2006 - 06:04 PM

For all natural numbers n, prove the following true or false:

is always divisible by 6

is always divisible by 6

Nothing!!!!!!!!

Posted 19 May 2006 - 06:05 PM

k^2 + k = k(k+1)

that's two consecutive integers, so one of them is even, so teh whole expression is even. Or you can consider cases of odd and even (i.e. let k=2n and then k=2n+1) and show it that way.

Yeah and then the whole thing is divisible by 6 and it turns out that n^3 - n is divisible by 6. I think I had this one in my Maths book..

Posted 19 May 2006 - 06:09 PM

it cums out as n n(n+1)(n-1)

2consecutive numbers meaning divisible by 2

also it it 3 consecutive meaning divisible by 3

cos 2 an 3 are prime it is divisible by 2 an 3

i.e 6

2consecutive numbers meaning divisible by 2

also it it 3 consecutive meaning divisible by 3

cos 2 an 3 are prime it is divisible by 2 an 3

i.e 6

Posted 19 May 2006 - 06:09 PM

For all natural numbers n, prove the following true or false:

is always divisible by 6

3 consecutive integers. Appeal to theorem that k consecutive integers is divisible by k! or say that one must be divisble by 3 and one must be divisible by 2, therefore whole expression is divisible by 6.

Posted 19 May 2006 - 06:14 PM

For all natural numbers n, prove the following true or false:

is always divisible by 6

3 consecutive integers. Appeal to theorem that k consecutive integers is divisible by k! or say that one must be divisble by 3 and one must be divisible by 2, therefore whole expression is divisible by 6.

thanks, i would never have guessed

who got T=40 for Q10

I got T= 60

The turning point was a Minimum at T=40. Which means you could increase the Temperature even further (tto the maximum allowed, which was 60) and get better Yeild. (I think)

i think i totally messed that one up

Nothing!!!!!!!!

Posted 19 May 2006 - 06:15 PM

how did u all do that temperature q?

Posted 19 May 2006 - 06:18 PM

i cant remember what my answer was think it was 60

you differentiated the original expression anfd then work out the stationary point and found the maximum that would be taken out ie when it would be most effective

you differentiated the original expression anfd then work out the stationary point and found the maximum that would be taken out ie when it would be most effective

Posted 19 May 2006 - 06:19 PM

Can anyone do the following:

By expressing as obtain in terms of x

By expressing as obtain in terms of x

Nothing!!!!!!!!

Posted 19 May 2006 - 06:21 PM

I got t= 20 probs wrong. I differentiated and then got T = 20 and T = 40 where 40 yields a minimum turning point and 20 yields a maximum

Posted 19 May 2006 - 06:23 PM

yeah i got something like that

Nothing!!!!!!!!

Posted 19 May 2006 - 06:29 PM

yeah i got something like that

bloody hell. its just a higher question then!!!??? i thought i wud be too easy to do that so i differenciated it again lol

it seemed like a higher question yeah. i dont know what the hell its doinig in the advanced higher

Nothing!!!!!!!!

Posted 19 May 2006 - 06:29 PM

i hate this paper

wish we had something along the lines of last year so you at least know if you are in the right area with your answers

wish we had something along the lines of last year so you at least know if you are in the right area with your answers

Posted 19 May 2006 - 06:31 PM

last years was much easier

Nothing!!!!!!!!

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