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# AH Maths 2006 Exam Post Mortem

### #121

Posted 20 May 2006 - 01:27 PM

### #123

Posted 20 May 2006 - 01:44 PM

therefore infinite solutions???

### #124

Posted 20 May 2006 - 01:47 PM

Both your answers appear to be right though?

therefore infinite solutions???

oooo i get it now

cos the gaussiam elimination was of the sytle that it had an infinite amount of solutions then you were supposed to say that it was infact redundant

can anyone back up what im saying?

### #125

Posted 20 May 2006 - 02:09 PM

so every one will be thinking they are right when in fact they are wrong as there solotion is only one of many

### #126

Posted 20 May 2006 - 02:12 PM

yes i can as lots of people here are getting results and if are put back into the equation then they will get the right answer but this is because the equations are redundent i.e infinite number of solutions

so every one will be thinking they are right when in fact they are wrong as there solotion is only one of many

thats kinda crap cos not many people will relise you will get loads of results

### #127

Posted 20 May 2006 - 02:34 PM

For 5 marks?

### #129

Posted 20 May 2006 - 03:18 PM

0 0 0 0

when there are 4 zeros that meens there are infinite solutions

### #130

Posted 20 May 2006 - 04:00 PM

### #131

Posted 20 May 2006 - 04:08 PM

I ain't sure if you had to do that, but hey

### #132

Posted 20 May 2006 - 04:31 PM

or sumthin alog those lines?

### #133

Posted 20 May 2006 - 05:01 PM

then the proper substitution gave B=0

differentiating gave:

substituting gave A=2

Back substitution :

not 100% sure if thats right, but that's what I did.

### #134

Posted 20 May 2006 - 05:41 PM

x = 1

and

y = 2z + 1

and the differential equation:

y = e^(-x)sin(x)

because when you differentiate it and substitute it it works so it should be correct..

### #135

Posted 20 May 2006 - 07:22 PM

x = 1

and

y = 2z + 1

and the differential equation:

y = e^(-x)sin(x)

because when you differentiate it and substitute it it works so it should be correct..

I got the same answer for the gaussian elimination but realised I made a mistake on the value of x in the exam. The differential equation I got y = 2e^-1(sinx)

### #136

Posted 20 May 2006 - 10:08 PM

A. Show that

B. By writing and using integration by parts, show that

C. Show that

D. Hence using the above results show that

### #137

Posted 21 May 2006 - 01:10 AM

### #138

Posted 21 May 2006 - 10:57 AM

Heres the question that everybody loves weeeeeeeeeeeee....

A. Show that

B. By writing and using integration by parts, show that

C. Show that

D. Hence using the above results show that

Do you reckon you got at least a B in the exam? You will regret it if you get a C, it will affect your 1st semester module choices for Maths at St Andrews if you get anything lower. And from somone who did it, you dont want to do MT1001 Introductory Maths... complete waste of time. Waste of a semester. Complete with a lecturer who is so bad that he can make you forget how to do Integration...

### #139

Posted 21 May 2006 - 01:52 PM

### #140

Posted 21 May 2006 - 02:27 PM

**eek!**

Mod edit: Ouch. My eyes.

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