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How It Go?


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#41 Adam

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Posted 17 May 2006 - 04:10 PM

(Err, this was actually me btw. I logged into an old account by accident. wink.gif)

I looked at the 2005 paper this morning and it seemed quite easy - it contained a lot of the questions which I hoped would have been in today's paper, but they rarely use the same question two years in a row.. so I knew today's paper wouldn't be easy. sad.gif

Today's paper wasn't bad... but it wasn't easy.

#42 SncZ

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Posted 17 May 2006 - 04:10 PM

QUOTE(Pyrefly @ May 17 2006, 04:49 PM) View Post

QUOTE
21a] W=mgcos =2600x9.8xcos12=24900N (to 3sf)


Uh oh....i thought it was mgsin angel....
*looks up notes*

weight acting down = mg....
mgsin angel is the force down the plane...hmm

for me i got the answer to be...
21a) 5297.6N
b) 1.5m s-2
c) 397488J (we were calculating the kinetic energy..not the velocity like you seem to have done..



i got the same biggrin.gif lets just hope its right eh smile.gif

#43 paddyb67

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Posted 17 May 2006 - 04:14 PM

QUOTE(adamcs @ May 17 2006, 04:53 PM) View Post


Are these definitely the correct answers? If so, I got 14/20, which I'd be quite pleased with. smile.gif I normally get around ~10/20...



yeah they'r right.

#44 Michael

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Posted 17 May 2006 - 04:15 PM

Yeah that looks correct for 21 I think.

#45 Dr-F

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Posted 17 May 2006 - 04:15 PM

QUOTE(nathanm @ May 17 2006, 05:07 PM) View Post

QUOTE
On the plus side...using the equation E = mc^2 in an exam was pretty damn gratifying lol.p


U not do credit maths last year then?


We were meant to use that last year??? huh.gif

#46 Michael

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Posted 17 May 2006 - 04:15 PM

Paddy can you PM me the answers please?

#47 Nathan

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Posted 17 May 2006 - 04:16 PM

QUOTE(Dr-F @ May 17 2006, 05:15 PM) View Post

QUOTE(nathanm @ May 17 2006, 05:07 PM) View Post

QUOTE
On the plus side...using the equation E = mc^2 in an exam was pretty damn gratifying lol.p


U not do credit maths last year then?


We were meant to use that last year??? huh.gif


it was one of them saying here is a formula, substitute in these numbers...the formula was E=mc2

#48 Dr-F

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Posted 17 May 2006 - 04:18 PM

QUOTE(nathanm @ May 17 2006, 05:16 PM) View Post

QUOTE(Dr-F @ May 17 2006, 05:15 PM) View Post

QUOTE(nathanm @ May 17 2006, 05:07 PM) View Post

QUOTE
On the plus side...using the equation E = mc^2 in an exam was pretty damn gratifying lol.p


U not do credit maths last year then?


We were meant to use that last year??? huh.gif


it was one of them saying here is a formula, substitute in these numbers...the formula was E=mc2


Ah...I remember it now. Still, using it and knowing what it means is a completely different experience


#49 ad absurdum

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Posted 17 May 2006 - 04:27 PM

QUOTE(paddyb67 @ May 17 2006, 05:14 PM) View Post

QUOTE(adamcs @ May 17 2006, 04:53 PM) View Post


Are these definitely the correct answers? If so, I got 14/20, which I'd be quite pleased with. smile.gif I normally get around ~10/20...



yeah they'r right. heres a few more answers:

22a) (iii) 1.4m/s upwards

23a) (i) 1.2celsius
b) (ii) 644.7 N
c) 3 solar panels

24) charge of proton = charge of electron
c)(i) 3.2E-17 J
(ii) 1.76E5 m/s

26a) (i) 250 Hz
(ii) -12
(iii)6.37V

Did your teacher give you the answers or something?

Anyway, hope your answers are right, cos that means I've got 100% for the multichoice tongue.gif
HMFC - Founded 1874, beefing the Cabbage since 1875

#50 Tracy

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Posted 17 May 2006 - 04:27 PM

Paddb67 your answer for 23ai is not right... for a start tempratures are all meant to be in KELVIN

Question 21 ©

Did anyone else find the final speed (v) at point B using the equations of motion BEFORE substituting v in for Ek = 0.5 * m * v *v and come out with a final answer of 135850J??

#51 paddyb67

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Posted 17 May 2006 - 04:28 PM

22a) (i) PR)OOF:
impulse = average Fxt
=35x0.01
=0.35Ns
(ii) 0.35 kgm/s upwards
(iii) 1.4m/s upwards

23a) (i) 1.2celsius
(ii) as T decreases, Ek of air molecules dcreases and so they move with less speed. they therefore hit the sides of the container with less momentum and so less force. p=F/A and so p decreases.
b) (i)F = A(P-P)
= 0.3x0.2(1.01E5 - 9.05E4)
= 630N
(ii) 644.7 N
(iii) equalizes pressure and so reduces downward force on lid, making it easier to take off.
c) 3 solar panels

24)a) it takes 200000J to move 1C of charge across a potntial of 200kV (other answrs possible)
b) protons are positively charged and so attracted to negatively charged Q.
c) charge of proton = charge of electron
(i) 3.2E-14 J
(ii) 1.76E5 m/s
d)no effect. pd is still the same and so kinetic energy is the same hence speed is the same

25)a) 2.2V
b)(ii)9V
(iii)1.34E-3 J
(iv) current starts at 0.04A

26a) (i) 250 Hz
(ii) -12
(iii)6.37V
b)(i) 10,47
(ii)R1 - 10
Rf - 47

27a)(ii) A - 4.48E-7 m
B - blue
(iii) caesium, strontium

b) 14.7

#52 Jade

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Posted 17 May 2006 - 04:31 PM

For Q24 (ci) I got

200kV=200000V

W=QV
1.60E-19 X 200000
=3.2E-14

Duno if thats right anyone get the same answer?

#53 paddyb67

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Posted 17 May 2006 - 04:32 PM

QUOTE(Tracy @ May 17 2006, 05:27 PM) View Post

Paddb67 your answer for 23ai is not right... for a start tempratures are all meant to be in KELVIN


you do the working in Kelvin, i just changed it back after as it gives you it in celsius.

#54 Michael

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Posted 17 May 2006 - 04:32 PM

It gives the initial temp in degrees C so i wrote it in K and in celcius

#55 KingBling

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Posted 17 May 2006 - 04:37 PM

Hey.
I think the exam was good for me, does anyone have a copy of the paper that they could email me or something please. Because I really want to know how well I did.
Thanks
smile.gif

#56 paddyb67

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Posted 17 May 2006 - 04:37 PM

QUOTE(Jade @ May 17 2006, 05:31 PM) View Post

For Q24 (ci) I got

200kV=200000V

W=QV
1.60E-19 X 200000
=3.2E-14

Duno if thats right anyone get the same answer?

yeah thats right i copid it out wrongly

#57 Pyrefly

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Posted 17 May 2006 - 04:38 PM

QUOTE
For Q24 (ci) I got

200kV=200000V

W=QV
1.60E-19 X 200000
=3.2E-14

Duno if thats right anyone get the same answer?


Thats what i got as well biggrin.gif

hopefully that means we are right...otherwise at least it wasn't only one of us that got it wrong biggrin.gif

#58 ice_illusion

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Posted 17 May 2006 - 04:39 PM

I wrote both.
The Celcius one was definately somewhere around 1.

#59 KingBling

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Posted 17 May 2006 - 04:44 PM

Please, Someone email me the paper. pleassse

#60 sarmad

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Posted 17 May 2006 - 04:44 PM

QUOTE(ice_illusion @ May 17 2006, 05:39 PM) View Post

I wrote both.
The Celcius one was definately somewhere around 1.


hi guys i thought the exam was a lot harder than last years, from the multichoice part it looks like i got 16, i have screwed up in the written part. Can sombody please post how they worked out the answers for question 26





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