Posted 04 May 2006 - 10:15 AM
Two forces acting on an aeroplane in flight are its weight and aerodynamic (lift) force.
The aerodynamic force acts in a direction perpendicular to the wings.
The pilot banks the aeroplane so that it flies at 150m/s in a horizontal circle of radius 4000m.
At what angle must the plane be banked?
Posted 05 May 2006 - 10:05 PM
As it is flying in a constant circle, centripetal force = horizontal component of weight.
Using vector triangles you can figure this out.
Wh = mg sin = mv2/r
sin = v2/rg
= sin-1 (v2/rg)
I got 35. I hope I'm right!
Posted 07 May 2006 - 06:52 PM
This question was in my prelim i think (or one similar) and i cant remember the whole thing but the answer turned out to what i scribbled out - it was something like 70 degrees (seemed rediculous).
I ll ask my teacher if i can see the marking scheme and i ll get back (hopefully)
Posted 09 May 2006 - 09:02 AM
At the time I was making a VERY stupid mistake, that was, central force = v^2/g , no m. And so had an extra m.
I feel so stupid.
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users