2002 Past Paper Q22ci
Posted 16 January 2006 - 04:52 PM
I tried using p=f/a but there is no area given that i can see.
Posted 16 January 2006 - 05:52 PM
T1 = (15+273)K = 288K
P2 = ?
T2 = (45+273)K = 318K
P1/T1 = P2/T2
P2 = P1T2/T1
P2 = 109x318/288
P2 = 120.35kPa
b. As the temperature increases the nitrogen gas molecules gain
kinetic energy. With increased kinetic energy the atoms are moving
faster and collide with the container walls more frequently
and forcefully. The pressure(force/area) therefore increases.
c.i. P = 1.75x105Pa
A = 4.0x10-6m2
F = PA
F = 1.75x105x4.0x10-6
F = 0.7N
c.ii. Read from the graph the length of the spring when the force
Length = 35mm
d. The assumption in the original set up is that the temperature
of the water is the same as the temperature of the gas inside
the flask. Placing the thermometer inside the flask will give
a more direct and accurate reading of the gas temperature.
Area of piston is given in Q as 4.0 x 10-6m2
Edited by nathanm, 16 January 2006 - 06:06 PM.
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