Sorry i can't put the question up but i don't know how to get the signs. Anyway can anyone tell me why when this is integrated, is the top line divided by the power+1(i get it so far) but then multiplied by 4?

I'm sure it's something simple but i just don't understand where the 4 came from

**0**

# Paper 1 2004, Question 7

Started by jambo david, Jan 14 2006 10:34 PM

7 replies to this topic

### #1

Posted 14 January 2006 - 10:34 PM

### #2

Posted 15 January 2006 - 11:35 AM

This particular integration is dealt with in Unit 3 of the course, Further Differentiation and Integration, so you may not have covered it yet!

I have attached a document which shows you the relevant way to start the problem, and I should just note that you wouldn't be given this formula in your exam.

If you require a bit more help in getting to the answer, as it is quite tricky, just put up another post!

Good luck!!

I have attached a document which shows you the relevant way to start the problem, and I should just note that you wouldn't be given this formula in your exam.

If you require a bit more help in getting to the answer, as it is quite tricky, just put up another post!

Good luck!!

#### Attached Files

### #3

Posted 15 January 2006 - 06:34 PM

QUOTE(aldo @ Jan 15 2006, 12:35 PM)

This particular integration is dealt with in Unit 3 of the course, Further Differentiation and Integration, so you may not have covered it yet!

I have attached a document which shows you the relevant way to start the problem, and I should just note that you wouldn't be given this formula in your exam.

If you require a bit more help in getting to the answer, as it is quite tricky, just put up another post!

Good luck!!

I have attached a document which shows you the relevant way to start the problem, and I should just note that you wouldn't be given this formula in your exam.

If you require a bit more help in getting to the answer, as it is quite tricky, just put up another post!

Good luck!!

Cheers very much, i was very confused, turns out i haven't done it yet so it won't be in my prelim tomorrow. I think i should be ok now

### #4

Posted 17 May 2006 - 09:42 PM

This particular integration is dealt with in Unit 3 of the course, Further Differentiation and Integration, so you may not have covered it yet!

I have attached a document which shows you the relevant way to start the problem, and I should just note that you wouldn't be given this formula in your exam.

If you require a bit more help in getting to the answer, as it is quite tricky, just put up another post!

Good luck!!

Can you please explain how you got the answer? I'm not sure what I'm doing wrong...

Cheers

### #5

Posted 18 May 2006 - 12:01 PM

Also, can somebody explain how to do

**Q8(a)**please?### #6

Posted 18 May 2006 - 12:10 PM

work out the centre and radius of the circle

then gradient of AP

then use m

then use y-b = m(x-a) to get your answer

then gradient of AP

then use m

_{1}m_{2}= -1 to get the gradient of the tangentthen use y-b = m(x-a) to get your answer

### #7

Posted 18 May 2006 - 12:13 PM

I think you're doing a different question

I'm talking about 2004 Paper 1 Q8

I'm talking about 2004 Paper 1 Q8

### #8

Posted 18 May 2006 - 12:23 PM

oops...i was lookin at paper 2

you should half an square the 10, to give you

x

thus (x-5)

you should half an square the 10, to give you

x

^{2}-10x + 25 -25 +27thus (x-5)

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