can anyone help me with drawing the graph of 2x2(2= squared) -2x?
thanks
SLJ
0
help
Started by south lanarkshire jag, Nov 11 2005 12:40 PM
5 replies to this topic
#2
-
- Members
-
- 602 posts
Child Prodigy
- Location:Western Isles
- Interests:playing the fiddle, swimming, music, the OC, Will and Grace and going out with friends. Not that there is much to do here!!
- Gender:Female
Posted 11 November 2005 - 12:42 PM
what's the equation I'm confused by the way you have written it! 
*a wee drop of heaven*
x sophie x
x sophie x
#3
-
- Members
-
- 359 posts
Top of the Class
- Gender:Male
Posted 11 November 2005 - 01:04 PM
(2x) all squared Subtract 2x
it's for a friend
it's for a friend
#4
-
- Members
-
- 602 posts
Child Prodigy
- Location:Western Isles
- Interests:playing the fiddle, swimming, music, the OC, Will and Grace and going out with friends. Not that there is much to do here!!
- Gender:Female
Posted 11 November 2005 - 02:00 PM
with the x being squared it sounds to me like it should be an up right parabola!
*a wee drop of heaven*
x sophie x
x sophie x
#5
-
- Members
-
- 56 posts
Good Effort
- Location:West Lothian
- Gender:Male
Posted 11 November 2005 - 03:05 PM
You can use software such as Excel (or your calculator) taking set values of x and calculating the corresponding y value.
I have attached what it should look like.
I have attached what it should look like.
#6
-
- Members
-
- 1,955 posts
Fully Fledged Genius
- Gender:Male
Posted 11 November 2005 - 06:12 PM
Just a quick run through of teh sketching procedure:
x = 0 or x = 1.
So now you know it cuts the x-axis through 0 and 1.
It cuts the y-axis when x = 0, so y = 0 also.
Lastly, find the turning points by differentiating and setting the derivative = 0.
So the x-coordinate of the turning point is x = 1/2 . For the y-coordinate:
So the turning point is (1/2 , -1/2).
Finally, you know its a parabola because it's a degree 2 polynomial, and that it has a minimum turning point (i.e. it's U shaped because the coefficient of x
is positive).
x = 0 or x = 1.So now you know it cuts the x-axis through 0 and 1.
It cuts the y-axis when x = 0, so y = 0 also.
Lastly, find the turning points by differentiating and setting the derivative = 0.
So the x-coordinate of the turning point is x = 1/2 . For the y-coordinate:
So the turning point is (1/2 , -1/2).
Finally, you know its a parabola because it's a degree 2 polynomial, and that it has a minimum turning point (i.e. it's U shaped because the coefficient of x
is positive).
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
