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Electronic Configuration - HSN forum

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Electronic Configuration


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#1 The Wedge Effect

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Posted 01 November 2005 - 09:21 PM

Hey, I know I'm not at school doing chemistry at AH, but I figured you might know a bit about electron configuration. So here's the problem. I'm not sure what to do for ions.

Here's the question:

3. Give the electronic configuration of:

a) Ca2+

c) O2-

Please help with this, don't have to give the answer, but an example answer like for say...Mg2+ might be of help. Thanks. smile.gif

p.s. it's stuff like 1S22s2 and whatever....

#2 KhalidBoussouara

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Posted 01 November 2005 - 10:02 PM

Ca is 1s22s22p63s23p64s2
but we lose 2 electrons in changing to a 2+ ion so the 4s2 becomes empty changing it to

Ca 2+ is then 1s22s22p63s23p6

O is 1s22s22p4
but we gain 2 electrons so that 2p shell gets an extra 2 in it to become

O2- is then 1s22s22p6
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#3 dfx

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Posted 01 November 2005 - 10:08 PM

Well Mg2+ would have lost 2 electrons from the outermost shell, so I take it would be:

1s power2.gif 2s power2.gif 2p power6.gif

Rem the for shell n = 1 you have orbital s with a maximum of 2 electrons.

n = 2, shell 2s with max 2 electrons and 2p with max 6 electrons (technically 2px, 2py, and 2pz each with 2 so total equals 6.)

n = 3 repeats n = 2 with the additional 3d orbital.

Just remember 4s is preferentially occupied before 3d (roughly same energy levels.)

I know thats pretty vague but I hope it helps. Any good textbook should sort it out.. smile.gif

#4 Katrina

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Posted 01 November 2005 - 10:08 PM

oh see while we are on this topic can you help me with this question:

What is the maximum number of electrons that can be accommodated in a d subshell?

#5 dfx

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Posted 01 November 2005 - 10:11 PM

D subshell max is 10 electrons, cause shell n = 3 has max of 18 electrons in all configured in  3s^2 3p^6 3d^{10}

#6 Katrina

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Posted 01 November 2005 - 10:13 PM

so n=1 has max of 2 n=2 has max of....8? and n=3 has max of 18. so wot about n=4?? how many n values can you get?

#7 The Wedge Effect

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Posted 01 November 2005 - 10:25 PM

Keep going...this is helping me with my uni work. biggrin.gif

#8 Katrina

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Posted 01 November 2005 - 10:26 PM

how can you be doing the same stuff as me but you're not in my classes?

#9 Katrina

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Posted 01 November 2005 - 10:41 PM

wedge have you done anything on angular functions yet?


#10 dfx

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Posted 02 November 2005 - 12:32 AM

I'm not too sure about n = 4... I THINK it's 32.. but I dno if you'd really have to know how to write configurations for elements that far down.

#11 The Wedge Effect

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Posted 02 November 2005 - 01:10 PM

QUOTE(Katrina @ Nov 1 2005, 10:41 PM)
wedge have you done anything on angular functions yet?

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Angular function...hmm...lemme think, is that to do with quantum numbers? You know...like n, l, m and s. I did that a few weeks ago and they were explaining how those functions were used in Schroedinger's equation and stuff like that.

#12 Katrina

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Posted 02 November 2005 - 06:10 PM

yes and you draw little circles on graphs, anyway do you know what the angular functions tell you about electron density?

#13 The Wedge Effect

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Posted 02 November 2005 - 07:05 PM

QUOTE(Katrina @ Nov 2 2005, 06:10 PM)
yes and you draw little circles on graphs, anyway do you know what the angular functions tell you about electron density?

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I'm not sure, they haven't told us anything about electron density. sad.gif

#14 Katrina

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Posted 08 November 2005 - 06:56 PM

could someone please help me with these questions?

20. Which of the following statements is INCORRECT?
(a) the orbital hybridisation of C in CH4 is sp2
(b) the orbital hybridisation of C in C6H6 is sp2
© the orbital hybridisation of C in C2H6 is sp3
(d) the orbital hybridisation of C in C2H4 is sp2
(e) the orbital hybridisation of C in C2H2 is sp

21. sp hybrid orbitals are formed in
(a) BeF2
(b) BCl3
© CCl4
(d) C2H6
(e) C2H4






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