**F(x) = e**

Can someone please show me how to do it.

Thanks!

Started by Floorball Maniac, Oct 01 2005 12:46 PM

8 replies to this topic

Posted 01 October 2005 - 12:57 PM

deriving from 1st principles

there is an equation which should be in your notes you just sub in values

i cant actually remember the equation and i binned my notes so not much help other than that

there is an equation which should be in your notes you just sub in values

i cant actually remember the equation and i binned my notes so not much help other than that

If i am not here i am somewhere else

Posted 01 October 2005 - 05:39 PM

The definition of the derivative of is

Posted 01 October 2005 - 08:10 PM

Okay

x -> e^x

x+h -> e^x+h

f(x+h) - f(x) / h = e^x+h - e^x / h

= e^x . e^h - e^x / h

= e^x (e^h -1) / h

** Taking out a common factor**

** Substitute into formula, Steve stated above**

f'(x) = lim h->0 f(x+h) - f(x) / h

= lim h->0 e^x (e^h -1) / h

= e^x . 1

= e^x

x -> e^x

x+h -> e^x+h

f(x+h) - f(x) / h = e^x+h - e^x / h

= e^x . e^h - e^x / h

= e^x (e^h -1) / h

f'(x) = lim h->0 f(x+h) - f(x) / h

= lim h->0 e^x (e^h -1) / h

= e^x . 1

= e^x

Mark

Posted 02 October 2005 - 11:05 AM

Yeah, so as it tends to infinity....

Posted 04 October 2005 - 06:57 PM

You can't go straight from to the answer since taking *h* to **zero** would require dividing by zero.

We have to get rid of the*h* on the bottom line somehow...

Suppose we have:

So .

Hope that helps in some way

We have to get rid of the

Suppose we have:

So .

Hope that helps in some way

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