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#1 Floorball Maniac

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Posted 15 September 2005 - 07:24 PM

This questions looks simple and I think I know how to do it. The only problem is I cant get the right answer. It's from Scholar. There could be a chance the answer is wrong. The question uses higher knowledge only.


A piano is being raised to the third floor of a building using a rope and pulley. The piano is m above the ground, moving upwards at m s -1 , when the rope snaps.
Calculate how much time (in s) elapses before the piano hits the ground.



Can someone do the question and see what they get.

Thanks in advance folks!

#2 dfx

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Posted 15 September 2005 - 08:31 PM

I think you left out the values...

#3 Floorball Maniac

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Posted 18 September 2005 - 02:14 PM

Obviously cant copy and paste from Scholar then. Never mind.

#4 werlop

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Posted 18 September 2005 - 05:36 PM

If you give me the values I can help.

You basically need to use  \[
s = ut + \frac{1}{2}at^2 
\]
as you know the initial velocity in the upwards (positive) direction, the acceleration due to gravity ( \[
9.8{\rm  ms}^{{\rm  - 1}} 
\]
), and the vertical displacement (s). The piano will continue upwards for a short period of time because of the acceleration due to gravity, and then accelerate downwards. ie there is a constant negative acceleration.
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