Warning: Illegal string offset 'html' in /home/hsn/public_html/forum/cache/skin_cache/cacheid_1/skin_topic.php on line 909

Volume calculation - HSN forum

# Volume calculation

2 replies to this topic

### #1Icemaiden

Top of the Class

• Members
• 375 posts
• Location:Falkirk
• Interests:Mwahahahaha!Attempting to dominate the world.

Posted 30 May 2005 - 07:32 PM

4NH3(g) + 5O2 --> 4NO(g) + 6H2O(l)

400L of oxygen is used up in the above reaction, measured under conditions in which its density is 1.6 g l-1.What mass of ammonia must have reacted?

I got 1.3kg but the book says 272g

Huggles

Ice Maiden
http://icemaiden04.deviantart.com

I'm a nutter in need of a new home (any offers?!? :P)

Cornish Pasty Pixie

"Its a new dawn,its a new day,its a new life for me....and i'm feeling good" -->Muse,Feeling good

### #2dfx

Fully Fledged Genius

• Members
• 1,955 posts
• Gender:Male

Posted 30 May 2005 - 07:40 PM

The density is 1.6 g/l . So 400 l is thus 460g.

460g of Oxygen is 20 moles (460/32 = 20 using n = m/gfm)

From the reaction, 4 moles NH3 reacts with 5 moles O2

Thus 16 moles of NH3 will react with 20 moles of O2

1 mole of NH3 is 17g

But 16 moles are reacting, somultiplied by 16 moles = 272g

Hope that helped

### #3Icemaiden

Top of the Class

• Members
• 375 posts
• Location:Falkirk
• Interests:Mwahahahaha!Attempting to dominate the world.

Posted 30 May 2005 - 07:47 PM

Thank-you....I think i went a bit wrong at the bottom in the mole ratios ..oops

Huggles

Ice Maiden
http://icemaiden04.deviantart.com

I'm a nutter in need of a new home (any offers?!? :P)

Cornish Pasty Pixie

"Its a new dawn,its a new day,its a new life for me....and i'm feeling good" -->Muse,Feeling good

#### 1 user(s) are reading this topic

0 members, 1 guests, 0 anonymous users