Q8b : Calculate the concentration of hydroxide ions in the 1mol l-1 HCl acid used in the experiment.
I do not understand why the concentration of H+ ions is 1x10 0 so the answer is 1x10 -14 mol l-1.
Anyone?
0
2004 - Written Paper - Q8(b)
Started by jamiep, May 30 2005 04:13 PM
4 replies to this topic
#2
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Posted 30 May 2005 - 04:21 PM
The total is always 1 x10^-14 So if the concentration of OH is 1 x 10^0, consequently the concentration of H+ ions will be 1 x 10^-14.
#3
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Posted 30 May 2005 - 04:23 PM
In scientific notation, 1 = 10^0, 0.1 = 10^-1, 0.01 = 10^-2 , etc.
1 mol / litre = 10^ 0 mol / litre because there are no 0's before the 1. Therefore, the conc. is 10 ^ -14. (Just think of the powers having to add together to give -14, so if you have 10 ^ -2 the other one has to be 10 ^ -12)
I hope you understand now
1 mol / litre = 10^ 0 mol / litre because there are no 0's before the 1. Therefore, the conc. is 10 ^ -14. (Just think of the powers having to add together to give -14, so if you have 10 ^ -2 the other one has to be 10 ^ -12)
I hope you understand now
#4
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Posted 30 May 2005 - 04:24 PM
pH=-log[H+]
[H+]=1
Therefor pH=-log[1]=0
So [OH-]=1 x 10^-14
Hope thatz right.
[H+]=1
Therefor pH=-log[1]=0
So [OH-]=1 x 10^-14
Hope thatz right.
#5
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Posted 30 May 2005 - 04:29 PM
*Lightbulb* 
Thanks for that guys, especially YIC, very clear!
Thanks for that guys, especially YIC, very clear!
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